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3 years ago

Which factors affect absorption and reflection of thermal energy? Check all that apply.

Physics

2 answers:

BigorU [14]3 years ago

7 0

Answer:

Correct answer is A and C

Explanation:

Absoption of thermal energy is process of transferring energy from one source to other source. Absoption depends on the wavelength of the radiation it means it depends on color and texture of the material.

Reflection:

Reflection is a phenomena in which radiation is incident from one medium to the surface of other medium and it come back to the same medium without entering in other medium. It depends on the wavelength of the radiation it means it depends on color and texture of the material

For example:

If you wore dark color cloths then you will feel hot because dark color absorb more heat similarly if you wore light cloth then you will not feel hot because light color reflects more radiation.

V125BC [204]3 years ago

4 0

A and C, The Color and Texture of the material.

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A river flows due south with a speed of 2.0 m/s .You steer a motorboat across the river; your velocity relative to the water is

mihalych1998 [28]

Answer:

a) $v_m =\sqrt{v^2_x + v^2_y} = \sqrt{(2m/s)^2 +(4.8 m/s)^2}= 5.2 m/s$

b) $\theta= tan^{-1} \frac{v_y}{v_x} = tan^{-1} (\frac{2}{4.8})= 22.62$ degrees and on this case to the South of the East.

c) $t= \frac{w}{v_m}= \frac{600m}{4.8 m/s}= 125 s$

d) $Y = 2 m/s * 125 s = 250m$

So it would be 250 to the South

Explanation:

Part a

For this case the figure attached shows the illustration for the problem.

We know that $v_y = 2 m/s$ represent the velocity of the river to the south.

We have the velocity of the motorboard relative to the water and on this case is $V_x= 4.8 m/s$

And we want to find the velocity of the motord board relative to the Earth $v_m$

And we can find this velocity from the Pythagorean Theorem.

$v_m =\sqrt{v^2_x + v^2_y} = \sqrt{(2m/s)^2 +(4.8 m/s)^2}= 5.2 m/s$

Part b

We can find the direction with the following formula:

$\theta= tan^{-1} \frac{v_y}{v_x} = tan^{-1} (\frac{2}{4.8})= 22.62$ degrees and on this case to the South of the East.

Part c

For this case we can use the following definition

$D = Vt$

The distance would be D = w = 600 m and the velocity V = 4.8m/s and if we solve for t we got:

$t= \frac{w}{v_m}= \frac{600m}{4.8 m/s}= 125 s$

Part d

For this case we can use the same definition but now using the y compnent we have:

$Y = v_y t$

And replacing we got:

$Y = 2 m/s * 125 s = 250m$

So it would be 250 to the South

7 0

3 years ago

Different between pulling and pushing force

yuradex [85]

Answer:

Push and pull are both forces, but the difference is in their direction at which it is applied. If the force applied in the direction of motion of the particle then we call it push. If that force applied in the direction OPPOSITE to the motion of the particle then it it termed as pull

4 0

3 years ago

17. A 25 kg block is initially at rest on a rough, horizontal surface. A horizontal force of 75 N is required to set

lapo4ka [179]

Answer:

0.30581

0.24464

Explanation:

$\mu_s$ = Coefficient of static friction

$\mu_k$ = Coefficient of kinetic friction

$F_f$ = 75 N

$F_k$ = 60 N

Normal force

$F_n=mg\\\Rightarrow F_n=25\times 9.81\\\Rightarrow F_n=245.25\ N$

Frictional force

$F_f=\mu_sF_n\\\Rightarrow \mu_s=\frac{F_f}{F_n}\\\Rightarrow \mu_s=\frac{75}{245.25}\\\Rightarrow \mu_s=0.30581$

The coefficient of static friction is 0.30581

Kinetic force

$F_k=\mu_kF_n\\\Rightarrow \mu_k=\frac{F_k}{F_n}\\\Rightarrow \mu_s=\frac{60}{245.25}\\\Rightarrow \mu_s=0.24464$

The coefficient of kinetic friction is 0.24464

4 0

3 years ago

__________________________ energy is the total kinetic energy of particles of matter. options: mechanical thermal electrical che

MissTica

Answer:

Thermal energy

Explanation:

I believe it is because the movement of particles has a connection with the temperature. Example: Since gas particles move very fast, it must be hot and freshly occurred through heating process.

7 0

4 years ago

) a stone is dropped from the top of a cliff. It is seen to hit the ground below after 3.55 s. How high is the cliff?

Agata [3.3K]

We use kinematic equation of motion,

$S =ut+ \frac{1}{2} gt^2$