Answer:https://global.oup.com/us/companion.websites/9780199385423/student/ch6/mcq/ just go here
Explanation:
Answer:
Cc= 12.7 lb.sec/ft
Explanation:
Given that
m = 22 lb
g= 32 ft/s²
![m = \dfrac{22}{32}=0.6875\ s^2/ft](https://tex.z-dn.net/?f=m%20%3D%20%5Cdfrac%7B22%7D%7B32%7D%3D0.6875%5C%20s%5E2%2Fft)
x= 4.5 in
1 in = 0.083 ft
x= 0.375 ft
Spring constant ,K
![K=\dfrac{m}{x}=\dfrac{22}{0.375}](https://tex.z-dn.net/?f=K%3D%5Cdfrac%7Bm%7D%7Bx%7D%3D%5Cdfrac%7B22%7D%7B0.375%7D)
K= 58.66 lb/ft
The damper coefficient for critically damped system
![C_c=2\sqrt{mK}](https://tex.z-dn.net/?f=C_c%3D2%5Csqrt%7BmK%7D)
![C_c=2\sqrt{0.6875\times 58.66}](https://tex.z-dn.net/?f=C_c%3D2%5Csqrt%7B0.6875%5Ctimes%2058.66%7D)
Cc= 12.7 lb.sec/ft
Answer:
A safety margin is the space left between your vehicle and the next to provide room, time and visibility at every instant
Explanation:
A safety margin is defined as an allowance given between your vehicle and the next vehicle in front to provide enough room, visibility and time to move in a safe manner to prevent the occurrence of an accident at anytime the frontal vehicle suddenly stops or slows down
Safety margins help minimize risks in the following way
1) A common knowledge of safety margins, improves predictability among road users, thereby minimizing the risk traffic accidents caused due to late communication
2) The use of safety margins helps minimize the risk due to a change in driving conditions such as when the road becomes more slippery from being covered with fluid that is being wetted
3) Safety margin can help prevent the occurrence of an accident between vehicles due to failure of a car system, such as a punctured tire or failed breaking system
4) Safety margin helps to protect road users from the introduction of obstacles on the main roads such as ongoing road construction, broken down vehicles, road blockage by vehicles involved in an accident etc
5) Safety margin help protect road users from being involved in an accident due to the loss of driving focus of the driver of the frontal vehicle
Answer:
4140 steel contains 0.4% C having higher yield strength and ultimate strength than the 1045 steel contains 0.45% C
Explanation:
we have given 4140 steel contains 0.4% C
we know here that 4140 steel is low steel alloy , and it have low amount of chromium , manganese etc alloying element
and these elements which are present in 4140 steel they increase yield strength and ultimate strength of steel
while in 1045 steel contains 0.45 % c is plain carbon steel
and it do not contain any alloying element
so that 4140 steel contains 0.4% C having higher yield strength and ultimate strength than the 1045 steel contains 0.45% C
The answer is number 2) Increase the resistance of the concrete to freeze-thaw damage.