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2 years ago

HELP ASAP

1 answer:

7 0

Benefits; is harmed

the parasite is benefited because they have somewhere to sleep, eat, and survive; whereas the host is harmed because the parasite is living on them and drinking their blood and causing other health issues

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Lipids with high polyunsaturatd fatty acid content are ____________ at room temperature.

kow [346]

The answer to this question would be liquid.

<span>Lipids with high polyunsaturated fatty acid mostly found as a liquid, but the saturated one would be solid at room temperature. A molecule with higher molecular weight will have the higher boiling point and it more likely to be solid at room temperature.
Unsaturated fat is more healthy than saturated fat and it is recommended to reduce saturated fat consumption as it was linked to many diseases.

</span>

7 0

4 years ago

100 PTS IM DESPERATE NEED BY TOMMOROW

faust18 [17]

Answer:

rest will do later mom is calling me plz understand promise will do it

Explanation:

Elements and compounds are similar in that they are both made of atoms and in some cases molecules.
Methods of Breaking Down Compounds
The only way to break down a compound is through a chemical change. Sometimes, energy is needed for a chemical change to happen. Two ways to add energy to break down a compound are to apply heat and to apply an electric current.

4 0

3 years ago

The equilibrium constant for the reaction AgBr(s) Picture Ag+(aq) + Br− (aq) is the solubility product constant, Ksp = 7.7 × 10−

barxatty [35]

Answer:

The reaction will be non spontaneous at these concentrations.

Explanation:

$AgBr(s)\rightarrow Ag^+(aq) + Br^- (aq)$

Expression for an equilibrium constant $K_c$ :

$K_c=\frac{[Ag^+][Br^-]}{[AgCl]}=\frac{[Ag^+][Br^-]}{1}=[Ag^+][Br^-]$

Solubility product of the reaction:

$K_{sp}=[Ag^+][Br^-]=K_c=7.7\times 10^{-13}$

Reaction between Gibb's free energy and equilibrium constant if given as:

$\Delta G^o=-2.303\times R\times T\times \log K_c$

$\Delta G^o=-2.303\times R\times T\times \log K_{sp}$

$\Delta G^o=-2.303\times 8.314 J/K mol\times 298 K\times \log[7.7\times 10^{-13}]$

$\Delta G^o=69,117.84 J/mol=69.117 kJ/mol$

Gibb's free energy when concentration $[Ag^+] = 1.0\times 10^{-2} M$ and $[Br^-] = 1.0\times 10^{-3} M$

Reaction quotient of an equilibrium = Q

$Q=[Ag^+][Br^-]=1.0\times 10^{-2} M\times 1.0\times 10^{-3} M=1.0\times 10^{-5}$

$\Delta G=\Delta G^o+(2.303\times R\times T\times \log Q)$

$\Delta G=69.117 kJ/mol+(2.303\times 8.314 Joule/mol K\times 298 K\times \log[1.0\times 10^{-5}])$

$\Delta G=40.588 kJ/mol$

For reaction to spontaneous reaction: $\Delta G$ .
For reaction to non spontaneous reaction: $\Delta G>0$ .

Since ,the value of Gibbs free energy is greater than zero which means reaction will be non spontaneous at these concentrations

5 0

3 years ago

How many penis enlargement pills can kill you?

Ray Of Light [21]

Answer:

to many

Explanation:

6 0

3 years ago

Read 2 more answers

Calculate the total heat flow, qtotal, when 15.0 g of water is cooled from 115°C to -20.0°C. The heat of fusion of water is 335

svet-max [94.6K]

Answer:The dependence of the density, viscosity, and heat capacity of a gas on the temperature. ... C-±r*j~d. (1.19). It Is very difficult to use Equation (1.19) for arbitrary quantities. Oi due tc the ... Equation (1.39) Is also valid for polyatomic g~ases whose tmolecules ... Nikuradze which involved the flow of water in long cylindrical tubes.

Explanation:

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3 years ago