Answer : The percent by mass of water the salt contain is, 55.3 %
Explanation : Given,
Mass of hydrated salt = 12.10 g
Mass of salt = 5.41 g
First we have to calculate the mass of water.
Mass of water = Mass of hydrate salt - Mass of salt
Mass of water = 12.10 g - 5.41 g
Mass of water = 6.69 g
Now we have to calculate the percent by mass of water the salt contain.

Now put all the given values in this expression, we get:


Therefore, the percent by mass of water the salt contain is, 55.3 %
Answer:
Mg²⁺(aq) + SO₃²⁻(aq) + 2 H⁺(aq) + 2 I⁻(aq) ⇄ Mg²⁺(aq) + 2I⁻(aq) + H₂O(l) + SO₂(g)
Explanation:
<em>Give the complete ionic equation for the reaction (if any) that occurs when aqueous solutions of MgSO₃ and HI are mixed.</em>
When MgSO₃ reacts with HI they experience a double displacement reaction, in which the cations and anions of each compound are exchanged, forming H₂SO₃ and MgI₂. At the same time, H₂SO₃ tends to decompose to H₂O and SO₂. The complete molecular equation is:
MgSO₃(aq) + 2 HI(aq) ⇄ MgI₂(aq) + H₂O(l) + SO₂(g)
In the complete ionic equation, species with ionic bonds dissociate into ions.
Mg²⁺(aq) + SO₃²⁻(aq) + 2 H⁺(aq) + 2 I⁻(aq) ⇄ Mg²⁺(aq) + 2I⁻(aq) + H₂O(l) + SO₂(g)
Answer:
The correct option is A
Explanation:
Some amino acids, called glucogenic amino acids, when catabolized convert there carbon backbones to tricarboxylic acid (TCA) cycle intermediates. These intermediates can be subsequently metabolized into carbon dioxide and water with the release of ATP or the formation of glucose (known as gluconeogenesis.
<u>All amino acids (with the exception of leucine and lysine) are glucogenic and can thus generate the carbon backbones required for gluconeogenesis</u>. Thus, the correct option is a.
Answer:
Eh, ni siquiera estoy haciendo química todavía, así que no puedo ayudarte amigo, también se supone que debo responder algunas preguntas aquí, así que...
Explanation:
No, I totally didn't use Google Translate for this. :)
Answer:
0.0011 M.
Explanation:
Molarity of a substance , is the number of moles present in a liter of solution .
M = n / V
M = molarity
V = volume of solution in liter ,
n = moles of solute ,
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
From the question ,
w = given mass of KMnO₄ = 0.0908 g
and ,
V = 0.500 L
Since ,
we know ,
m = Molecular mass of KMnO₄ = 158 g/mol
using , the above formula to calculate the moles ,
n = w / m = 0.0908 g / 158 g/mol = 0.00057 mol
now , calculating the molarity as ,
M = n / V = 0.00057 mol / 0.500 L = 0.0011 M.