Answer is: <span>solubility of cadmium carbonate is 0,00017 g/L.
</span>Cadmium carbonate in water: CdCO₃ → Cd²⁺ + CO₃²⁻.
[Cd²⁺] = [CO₃²⁻] = x.
Ksp = [Cd²⁺] · [CO₃²⁻].
10⁻¹² = x².
x= √10⁻¹².
x = [Cd²⁺] = [CO₃²⁻] = 10⁻⁶ mol/L.
[CdCO₃] = 10⁻⁶ mol/L.
n(CdCO₃) = 10⁻⁶ mol/L · 1 L = 10⁻⁶ mol.
m(CdCO₃) = n(CdCO₃) · M(CdCO₃).
m(CdCO₃) = 10⁻⁶ mol · 172,41 g/mol.
m(CdCO₃) = 0,00017 g/L.
Group 1 and group 7 of element group consists of alkali metal, which are generally combined with other elements in nature, so they have properties of compound
The answer is B. bases measure below seven
think of it like this 7 is neutral going down from seven it rises in acidity and going up from seven increases in alkalinity