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adell [148]
3 years ago
13

4) What is the IUPAC name of this compound?

Chemistry
1 answer:
zheka24 [161]3 years ago
8 0

Answer:

1,3- dichlorobutane

Explanation:

The IUPAC name of given compound is 1,3- dichlorobutane.

First of all we will select the longest chain.

The given compound is straight chain. So the compound have four carbon atoms means parent name will butane.

Then we will see the position of functional group. Gives the lowest possible number to the functional group attached.

In given compound one chlorine atom is attached on left side and other is on right side. we will start the numbering from left because in this way chlorine will get lowest possible number which 1 and 3.

As we start the numbering from left the one chlorine atom get number one and other is attached on carbon 3 will have number 3.

There are two chlorine atoms so we will give name "dichloro"

The name will be,

⁴CH₃-³CHCl-²CH₂-¹CH₂Cl

1,3- dichlorobutane.

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Write the balanced chemical equation for the neutralization reaction that occurs when an aqueous solution of hydrochloric acid (
Vladimir79 [104]

Answer:

HCl(aq) + KOH(aq) —> KCl(aq) + H2O(l)

Explanation:

Aqueous solution of HCl and aqueous solution of KOH react as follow:

HCl(aq) + KOH(aq) —>

In solution, HCl and KOH will dissociates as follow:

HCl —> H+ + Cl-

KOH —> K+ + OH-

During the reaction, a double displacement reaction occur as shown below:

H+ + Cl- + K+ + OH- —> K+Cl- + H+OH-

The elemental equation is given below:

HCl(aq) + KOH(aq) —> KCl(aq) + H2O(l)

8 0
3 years ago
Read 2 more answers
uppose the reaction Ca3(PO4)2 + 3H2SO4 ï‚® 3CaSO4 + 2H3PO4 is carried out starting with 153 g of Ca3(PO4)2 and 87.6 g of H2SO4.
aleksklad [387]

The answer is 58.4 g of H₃PO₄

Given that mass of Ca₃(PO₄)₂ is 153g

mass of H₂SO₄ is 87.6g

We need to calculate the mass of H₃PO₄

So the balanced chemical reaction is

Ca₃(PO₄)₂  +  3H₂SO₄  ⇒   3CaSO₄  +  2H₃PO₄

Let us calculate the molar mass of the reactants

Ca₃(PO₄)₂ = (3 x 40) + (2 x 31) + (8 x 16)

= 120 + 62 + 128

= 310 g

H₂SO₄ = (1 x 2) + (32 x 1) + (16 x 4)

= 2 + 32 + 64

= 98 g

Now let us calculate the limiting reactant

The Theoretical Yield =  Ca₃(PO₄)₂ / H₂SO₄

= 310 / 3(98)

= 1.05

The Experimental yield

Ca₃(PO₄)₂ / H₂SO₄

= 153 / 87.6 = 1.74

Because the observed percentage was more than the predicted proportion, H2SO4 is the limiting reactant.

Let us Calculate the molar mass of H₃PO₄

H₃PO₄ = (1 x 3) + (31 x 1) + (16 x 4)

= 3 + 31 + 64

= 98 g

Now Calculate the mass of H₃PO₄

3(98) g of H₂SO₄ ------------------ 2(98) g of H₃PO₄

87.6 g of H₂SO₄ ------------------  x

x = ( 87.6 x 2 x 98) / (3 x 98)

x = 17169.6 / 294

x = 58.4g of H₃PO₄

Learn more about Theoretical Yield here

brainly.com/question/25996347

#SPJ1

4 0
2 years ago
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