Answer:
it's
C. with melting point 11° C and boiling point 181° C
Explanation:
i hope you got it
Answer : The rate of effusion of sulfur dioxide gas is 52 mL/s.
Solution :
According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

or,
..........(1)
where,
= rate of effusion of nitrogen gas = 
= rate of effusion of sulfur dioxide gas = ?
= molar mass of nitrogen gas = 28 g/mole
= molar mass of sulfur dioxide gas = 64 g/mole
Now put all the given values in the above formula 1, we get:


Therefore, the rate of effusion of sulfur dioxide gas is 52 mL/s.
Answer:
yes, if they were in rest they would have potential energy
Explanation:
Answer:
its shorter than a regular one
Explanation:
the only reason is simply because it is shorter
Answer:Is this from the stochiometry unit?
Explanation: