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2 years ago

Ch3chclch(ch3)ch2ch2ch2ch2br name the molecule iupac rules please

Chemistry

1 answer:

nadezda [96]2 years ago

4 0

Answer:

1-bromo-6-chloro-5-methylheptane

Explanation:

There are 3 substituents, 1 chlorine, 1 bromine, and 1 methyl group.

The longest carbon chain consists of 7 carbons.

There are no double bonds, based on the saturation and substituents.

So you have a 1-bromo-6-chloro-5-methylheptane.

Hope that was the brainliest answer!

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PLEASE HELP!!!!!!! CHEMISTRY!!!!

AnnZ [28]

Answer:

dude im sorry for your loss best of luck to you and your answer search

Explanation:

3 0

3 years ago

Determine the pH of 0.050 M HCN solution. HCN is a weak acid with a Ka equal to 4.9 x 10-10<br> DONE

nadezda [96]

Answer:

The pH of the solution is 5.31.

Explanation:

Let " $\alpha$ is the dissociation of weak acid - HCN.

The dissociation reaction of HCN is as follows.

$HCN+H_{2}O\rightarrow H_{3}O^{+}+CN^{-}$

Initial C 0 0

Equilibrium c(1- $\alpha$ ) c $\alpha$ c $\alpha$

Dissociation constant = $Ka= c\alpha \times \frac{c\alpha}{c(1-\alpha)}$

$=\frac{c\alpha^{2}}{(1-\alpha)}$

In this case weak acids $\alpha$ is very small so, (1- $\alpha$ ) is taken as 1.

$Ka=C\alpha^{2}$

$\alpha=\sqrt\frac{ka}{c}$

From the given the concentration = 0.050 M

Substitute the given value.

$\alpha=\sqrt\frac{4.9\times 10^{-10}}{0.05}=9.8\times 10^{-4}$

$[H_{3}O^{+}]=c\alpha$

$[H_{3}O^{+}]=0.05\times 9.8\times 10^{-4}= 4.9\times10^{-6}$

$pH= -log[H_{3}O^{+}]$

$=-log[4.9\times10^{-6}]$

$=6-log 4.9= 5.31$

Therefore, The pH of the solution is 5.31.

7 0

3 years ago

Read 2 more answers

How are you in the morning i want to take a nap

LekaFEV [45]

Sameee! I just wake up and I already wanna go take a nap lol

3 0

3 years ago

Read 2 more answers

An ice cube tray full of water is put into a freezer. Which energy change occurs in the particles in the water as it undergoes a

o-na [289]

Answer:

Explanation:

increase in energy - hotter and/or more reactive

decrease in energy - colder and/or less reactive

Since it is going from a liquid to solid it will have a tighter arrangement of particles.

3 0

2 years ago

Use the balanced equation from number four above to determine the limiting reactant if we had a mixture of 5.0 moles of Fe and 4

Tom [10]

Answer:

2Fe + 3O₂ → 2Fe₂O₃

Limiting reactant: O₂

2Fe + O₂ → 2FeO

Limiting reactant: Fe

Explanation:

2Fe + 3O₂ → 2Fe₂O₃

2Fe + O₂ → 2FeO

These are the possible reactions:

In first case, 2 moles of Fe need 3 mol of oyxgen to react

If I have 5 moles of Fe, I will need (5 .3)/2 = 7.5 moles of O₂

Then, the oxygen is my limiting ( I only have 4 moles)

3 moles of O₂ need 2 moles of Fe

If I have 4 moles of O₂, I will need (4 .2)/3 = 2.66 moles (I have 5)

Fe, is the reactant in excess.

For second case, 2 moles of Fe need 1 mol of O₂, to react.

If I have 5 moles of Fe, I will need ( 5 .1) / 2 =2.5 moles of O₂

I have 4 moles of oxygen, so now it is my excess.

1 mol of O₂ need 2 moles of Fe, to react

If I have 4 moles of O₂, I will need the double of amount, 8 moles of Fe.

I have 5 moles, then the Fe is my limtiing reactant.

8 0

3 years ago