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elena-14-01-66 [18.8K]
3 years ago
10

I need help with these science questions, leave explanations please.

Physics
2 answers:
dimaraw [331]3 years ago
6 0
Hello there.

<span>Which acid will undergo 100% dissociation when dissolved in water?

Answer:</span><span> HCL
</span><span>
Option: C

Second Question...not sure.



</span>
luda_lava [24]3 years ago
4 0

1.

Answer:

C) HCL

Explanation:

here HCL is 100% dissolved in the water because electronegativity difference between H and CL is sufficiently high and it will easily dissociate the charge into two ions.

So here correct answer will be

C). HCL

2.

Answer:

A) 2

Explanation:

Electrical power is defined in terms of current and resistance as

P = i^2R

now we will have current is doubled but resistance is halved

so change will be given as

P' = (2i)^2(\frac{R}{2})

so we have

P' = 2P

so here power is doubled

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In order to make things easier to describe and explain, let's call
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a).  In series, the total resistance is 3R.
In parallel, the total resistance is R/3.
Changing from series to parallel, the total resistance of the circuit
decreases to 1/9 of its original value.

b).  In series, the total current is  V / (3R) .
In parallel, the total current is  3V / R .
Changing from series to parallel, the total current in the circuit
increases to 9 times its original value.

c).  In series, the power dissipated by the circuit is 

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In parallel, the power dissipated by the circuit is

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Changing from series to parallel, the power dissipated by
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3 years ago
Referring to the graph below of data describing a cart pulled across a level surface. When a 4 N force pulls on the cart, the ca
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3 years ago
A train at a constant 60.0 km/h moves east for 40.0 min, then in a direction 50.0 degrees east of due north for 20.0 min, and th
son4ous [18]

Answer:

Part a)

v = 7.57 km/h

Part b)

\theta = 67.5 degreeNorth of East

Explanation:

Speed of train towards East = 60 km/h

displacement towards East is given as

d_1 = 40 km

now it turns towards 50 degree East of North

so its distance is given as

d_2 = 20 km(sin50 \hat i + cos50\hat j)

d_2 = 15.3 \hat i + 12.8 \hat j

then finally it moves towards west for 50 min

d_3 = -50 \hat i

Now the total displacement of the train is given as

d = d_1 + d_2 + d_3

d = (40 + 15.3 - 50)\hat i + 12.8 \hat j

d = 5.3\hat i + 12.8 \hat j

now total time duration of the motion is given as

T = 40 min + 20 min + 50 min

T = 1.83 h

now average velocity is given as

v_{avg} = \frac{5.3\hat i + 12.8\hat j}{1.83}

v_{avg} = 2.89\hat i + 6.99\hat j

Part a)

magnitude of the average velocity is given as

v = \sqrt{v_x^2 + v_y^2}

v = \sqrt{2.89^2 + 6.99^2}

v = 7.57 km/h

Part b)

Direction of the velocity is given as

tan\theta = \frac{v_y}{v_x}

tan\theta = \frac{6.99}{2.89}

\theta = 67.5 degreeNorth of East

6 0
3 years ago
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