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Vedmedyk [2.9K]
3 years ago
12

A football is kicked at ground level with the speed of 32 m/s at an angle of 40 degrees to the horizontal. how much later does i

t hit the ground?
Physics
1 answer:
LUCKY_DIMON [66]3 years ago
4 0
the question was a football is kicked at ground level with a speed of 32 m/s the an angle of 40 degrees to the horizontal how much later does it hit the ground probably like 30 more or 40 sense it was around 32
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Take the mechanical equivalent of heat as 4 J/cal. A 10-g bullet moving at 2000 m/s plunges
klasskru [66]

Assuming that all the bullet’s energy heats the paraffin, its final temperature is 27.1 degree C. The correct option is D.

<h3>What is temperature?</h3>

Temperature is the degree of hotness and coldness of the material.

The energy of the bullet E = 1/2 mv²

E = 1/2 x 10 x 10⁻³ x (2000)²

E = 2 x 10⁴ J

This heat is used in heating the paraffin

E = m x c ΔT = m x c (Tfinal -Tinitial)

2 x 10⁴ J = 1 x 2.8 x 10³ x (Tfinal -20)

Tfinal = 27.1°C

Thus, the final temperature is 27.1 degree C. The correct option is D.

Learn more about temperature.

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2 years ago
What is potential difference also called?
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Voltage - V = IR : v= voltage i= current r= resistance
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3 years ago
What does the energy hill represent on an energy diagram?
creativ13 [48]

Answer:

In my opinion I think the answer is C you don't have to choose C

8 0
3 years ago
The equation of a transverse wave traveling along a string is given by y=0.3sin (0.5x-50t) find the maximum displacement of the
uysha [10]

Answer:

0.3cm

Explanation:

Y = 0.3 sin(0.5x - 50t) compare with,

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A = 0.3m

5 0
2 years ago
The water line from the street to my house is 1 inch diameter and made of PVC (i.e. smooth). The line is roughly 450 ft long. Th
jekas [21]

Answer:

The right solution is "126 Psi".

Explanation:

The given values are:

P₁ = 130 psig

i.e.,

   = 130\times 6.894

   = 896.22 \ Kpa

or,

   = 896.22\times 10^3 \ Pa

Z₂ = 10ft

    = 3.05 m

\delta = 1000 kg/m³

According to the question,

Z₁ = 0

V₁ = V₂

As we know,

⇒  \frac{P_1}{\delta_g} +\frac{V_1^2}{2g} +Z_1=\frac{P_2}{\delta_g} +\frac{V_2^2}{2g} +Z_2

On substituting the values, we get

⇒  \frac{P_1}{\delta_g} +0+0=\frac{P_2}{\delta_g} +0+Z_2

⇒  \frac{896.22\times 10^3}{1000\times 9.8} =\frac{P_2}{1000\times 9.8} +3.05

⇒  P_2=866330 \ P_a

i.e.,

⇒       =866330\times 0.000145

⇒       =126 \ Psi

8 0
2 years ago
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