<span>C.CT scan, X-ray imaging, MRI
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This has to do with independent and dependent variables. The independent variable is what affects the dependant variable, so the question is, does a students mark on a test affect their hours of sleep or does their hours of sleep affect their test results? Which one makes more sense? I would say the latter.
(1) The linear acceleration of the yoyo is 3.21 m/s².
(2) The angular acceleration of the yoyo is 80.25 rad/s²
(3) The weight of the yoyo is 1.47 N
(4) The tension in the rope is 1.47 N.
(5) The angular speed of the yoyo is 71.385 rad/s.
<h3> Linear acceleration of the yoyo</h3>
The linear acceleration of the yoyo is calculated by applying the principle of conservation of angular momentum.
∑τ = Iα
rT - Rf = Iα
where;
- I is moment of inertia
- α is angular acceleration
- T is tension in the rope
- r is inner radius
- R is outer radius
- f is frictional force
rT - Rf = Iα ----- (1)
T - f = Ma -------- (2)
a = Rα
where;
- a is the linear acceleration of the yoyo
Torque equation for frictional force;

solve (1) and (2)

since the yoyo is pulled in vertical direction, T = mg 
<h3>Angular acceleration of the yoyo</h3>
α = a/R
α = 3.21/0.04
α = 80.25 rad/s²
<h3>Weight of the yoyo</h3>
W = mg
W = 0.15 x 9.8 = 1.47 N
<h3>Tension in the rope </h3>
T = mg = 1.47 N
<h3>Angular speed of the yoyo </h3>
v² = u² + 2as
v² = 0 + 2(3.21)(1.27)
v² = 8.1534
v = √8.1534
v = 2.855 m/s
ω = v/R
ω = 2.855/0.04
ω = 71.385 rad/s
Learn more about angular speed here: brainly.com/question/6860269
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Answer: final Displacement = 0 km, total distance covered =7 km
Explanation:
Given the following :
From home to library = 1.3 km East
Library to music store = 0.68km East
Music store to friend's house = 1.1km North
Friend's house to grocery store = 0.42 km North
Displacement is the net change in distance traveled.
Eastward distance :
To = (1.3 + 0.68)km = 1.98km East
Fro = (0.68 + 1.3)km = 1.98 km East
Δ distance = (1.98 - 1.98) = 0
Northward direction:
To = (1.1 + 0.42)km = 1.52km north
Fro = (0.42 + 1.1)km = 1.52km North
Δ distance = (1.98 - 1.98) = 0
Hence final Displacement = 0
Total distance covered = 2 × (1.3 + 0.68 + 1.1 + 0.42) = 2 × 3.5
= 7km
Answer:
El neumático soportará una presión de 1.7 atm.
Explanation:
Podemos encontrar la presión final del neumático usando la ecuación del gas ideal:

En donde:
P: es la presión
V: es el volumen
n: es el número de moles del gas
R: es la constante de gases ideales
T: es la temperatura
Cuando el neumático soporta la presión inicial tenemos:
P₁ = 1.5 atm
T₁ = 300 K
(1)
La presión cuando T = 67 °C es:
(2)
Dado que V₁ = V₂ (el volumen del neumático no cambia), al introducir la ecuación (1) en la ecuación (2) podemos encontrar la presión final:
Por lo tanto, si en el transcurso de un viaje las ruedas alcanzan una temperatura de 67 ºC, el neumático soportará una presión de 1.7 atm.
Espero que te sea de utilidad!