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lozanna [386]
3 years ago
15

You are holding a string tied to a lamp post 15 m away. You pull the string so that it has a tension of 1.5 N and a mass density

of 0.0045 kg/m. You shake the end of the string at 4 Hz. What is the wavelength of the wave you generate in m
Physics
1 answer:
Dvinal [7]3 years ago
6 0

Answer:

Explanation:

Given that

L= 15 m

T= 1.5 N

μ =0.0045 kg/m

f= 4 Hz

We know that

Velocity in string V is given as

V=\sqrt{\frac{T}{\mu}}

Now putting the values in the above equation we get

V=\sqrt{\frac{1.5}{0.0045}}=18.25\ m/s

We know that

V= f λ

\lambda =\frac{V}{f}

\lambda =\frac{18.25}{4}=4.5 m

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Answer:

I am confused of your question. Do you want final velocity? To get final velocity, use (initial V)+(Gravity*Time)

Explanation:

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Answer:

684J

Explanation:

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We don't have the mass but since we have the height, we multiply directly with the height since the quantity of weight is already given.

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3 years ago
Find the sum 5.24 g, 43.261 g, and 7.3458 g. Write your answer with the correct amount of significant figures.
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Answer:

This is how I do it:

  • 5.24 rounded to one significant figure is 5
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Explanation:

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A person is standing on a raft; their
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Answer:

The volume of water displaced by the raft is 0.233 m³

Explanation:

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The given parameters are;

The combined mass of the person and the raft, m = 233 kg

The liquid on which the raft is located = Water

The density of water, \rho _{water} = 1000 kg/m³

Weight = Mass, m × g

Where;

m = The mass of the object

g = The acceleration due to gravity = 9.8 m/s²

Given that the raft is on the surface of the water (floating), the buoyant force is equal to the combined weight of the person and the raft = 233 kg

The combined weight of the person and the raft, W_{combined} = 233 kg × 9.8 m/s² = 2,283.4 N

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The buoyant force = 2,283.4 N = The weight of the water displaced

The mass of the water displaced, m_{water}, = 2,283.4 N/(9.8 m/s²) = 233 kg

Density = Mass/Volume

The volume of water displaced by the raft = The mass of the water displaced/(The density of the water) = 233 kg/(1,000 kg/m³) = 0.233 m³.

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