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lozanna [386]
3 years ago
15

You are holding a string tied to a lamp post 15 m away. You pull the string so that it has a tension of 1.5 N and a mass density

of 0.0045 kg/m. You shake the end of the string at 4 Hz. What is the wavelength of the wave you generate in m
Physics
1 answer:
Dvinal [7]3 years ago
6 0

Answer:

Explanation:

Given that

L= 15 m

T= 1.5 N

μ =0.0045 kg/m

f= 4 Hz

We know that

Velocity in string V is given as

V=\sqrt{\frac{T}{\mu}}

Now putting the values in the above equation we get

V=\sqrt{\frac{1.5}{0.0045}}=18.25\ m/s

We know that

V= f λ

\lambda =\frac{V}{f}

\lambda =\frac{18.25}{4}=4.5 m

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Oksi-84 [34.3K]

Answer:

Explanation:

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You need to remove a broken light bulb from a lamp. without a pair of gloves, you are likely to cut yourself on the jagged glass
mojhsa [17]
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The launching velocity of a missile is 20.0 m/s, and it is shot at 53º above the horizontal. What is the vertical component of t
Lyrx [107]

Given that

Velocity of missile (v) = 20 m/s ,

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Determine ,   Vertical component  = v sin Θ

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6 0
3 years ago
A satellite orbits the earth a distance of 1.50 × 107 m above the planet's surface and takes 8.65 hours for each revolution abou
kupik [55]

Answer:

The acceleration of the satellite is 0.87 m/s^{2}

Explanation:

The acceleration in a circular motion is defined as:

a = \frac{v^{2}}{r}  (1)

Where a is the centripetal acceleration, v the velocity and r is the radius.

The equation of the orbital velocity is defined as

v = \frac{2 \pi r}{T} (2)

Where r is the radius and T is the period

For this particular case, the radius will be the sum of the high of the satellite (1.50x10^{7} m) and the Earth radius (6.38x10^{6} m) :

r = 1.50x10^{7} m+6.38x10^{6}m

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T = 8.65 hrs \cdot \frac{3600 s}{1hrs} ⇒ 31140 s

v = \frac{2 \pi (21.38x10^{6}m)}{31140s}

v = 4313 m/s

Finally equation 1 can be used:

a = \frac{(4313m/s)^{2}}{21.38x10^{6}m}    

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Hence, the acceleration of the satellite is 0.87 m/s^{2}

6 0
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Jlenok [28]

Answer:

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