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Kruka [31]
3 years ago
10

An object becomes positively charged when it

Physics
1 answer:
Montano1993 [528]3 years ago
8 0

Answer:

D

Explanation:

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A force of 500 N is used to slide a box across a smooth surface; the box moved 5 m in 1.2 seconds. What power is used?
Katen [24]
F = 500N
S = 5m
T = 1.2s
----------------------------------
P = ?

We can use formula P = F * V, just because it was a smooth slide we can assume that average speed was V = S/T = 5 / 1.2 = 50/12

So the final answer would be:

P = F * V = 500 * 50/12

Are you sure those are correct numbers? The answer don't look nice :D



8 0
3 years ago
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Motion is changing all the time. When you stand up, begin to run, or turn a corner, your motion is changing. These changes in mo
Andrej [43]

Answer:

push on objects force is required. pull force is resli8

6 0
2 years ago
In xray machines, electrons are subjected to electric fields as great as 6.0 x 10^5 N/C. Find
katrin2010 [14]

Answer:

a = 1.055 x 10¹⁷ m/s²

Explanation:

First, we will find the force on electron:

E = \frac{F}{q}\\\\F = Eq\\

where,

F = Force = ?

E = Electric Field = 6 x 10⁵ N/C

q = charge on electron = 1.6 x 10⁻¹⁹ C

Therefore,

F = (6\ x\ 10^5\ N/C)(1.6\ x\ 10^{-19}\ C)\\

F = 9.6 x 10⁻¹⁴ N

Now, we will calculate the acceleration using Newton's Second Law:

F = ma\\a = \frac{F}{m}\\

where,

a = acceleration = ?

m = mass of electron = 9.1 x 10⁻³¹ kg

therefore,

a = \frac{9.6\ x\ 10^{-14}\ N}{9.1\ x\ 10^{-31}\ kg}\\\\

<u>a = 1.055 x 10¹⁷ m/s²</u>

5 0
3 years ago
how do you Compute the approximate acceleration of gravity for an object above the earth's surface, assigning accel gravity with
solong [7]

The approximate acceleration of gravity for an object above the earth's surface is 9.8 m/s².

<h3>Acceleration due to gravity </h3>

The acceleration due to gravity of an object above the Earth's surface is calculated from Newton's second law of motion and Newton's law of universal gravitation.

<h3>Force between the object and Earth</h3>

F_g = \frac{GmM}{R^2}

<h3>Weight of the object</h3>

F_g = mg\\

Solve (1) and (2)

mg = GmM/R²

g = GM/R²

where;

  • M is mass of Earth
  • G is gravitational constant
  • R is radius of the Earth = 6,371 km

g = (6.673 x 10⁻¹¹ x 5.98 x 10²⁴)/(6,371 x 10³)²

g = 9.8 m/s²

Learn more about acceleration due to gravity here: brainly.com/question/88039

#SPJ1

7 0
2 years ago
The total length of the wire of potentiometer is 10m. A potential gradient of 0.0015 V/cm is obtained when a steady current is p
andreyandreev [35.5K]

Answer:

this picture might help you

Explanation:

if you think correct pls mark brainliest

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