All categories

3 years ago

If a cannonball is fired horizontally from a cannon high atop a mountain, its____?

Physics

2 answers:

den301095 [7]3 years ago

7 0

Answer: If you have to choose a sentence in a paragraph on this

Select the correct text in the passage.

Which two words enhance the setting in this poem?

War

by Ellen Glasgow

Ripples of ribbons borne on high,

Bloodstains upon a brazen sky;

From cannon belching on the plain,

Fire that by fire is fought again.

A flash where steel by steel is met;

A fume of smoke and blood and sweat.

Sharp from the smeared and trodden gorse

The death-cry of a wounded horse.

Dust of a plain ground into red

By armies of majestic dead.

Gaunt shadows on the changeless sky,

A flock of vultures swarming nigh.

Mid ashes where a hearth has stood,

Children that cry aloud for food.

Where green the peaceful highways run,

A woman ravished in the sun.

And far across the reeking sod

A Nation sounding thanks to God.

Answer from plato is -Brazen and Reeking

Explanation:

mel-nik [20]3 years ago

5 0

Acceleration due to gravity will be constant, but the speed can change.

You might be interested in

A ball on an extremely low-friction, tilted surface will slide downhill without rotating. If the surface is rough, however, the

spayn [35]

It will go left or right

6 0

3 years ago

A car accelerates in the +x direction from rest with a constant acceleration of a1 = 1.62 m/s2 for t1 = 20 s. At that point the

arsen [322]

Total displacement of the car: 405 m

Explanation:

The first part of the motion of the car is a uniformly accelerated motion, so we can use the suvat equation

$s_1=ut_1+\frac{1}{2}a_1 t_1^2$

where:

u = 0 is the initial velocity (the car starts from rest)

$t_1 = 20 s$ is the time elapsed in the 1st part

$a_1=1.62 m/s^2$ is the acceleration of the car in the 1st part

$s_1$ is the displacement of the car in the 1st part

Solving for $s_1$ ,

$s_1=0+\frac{1}{2}(1.62)(20)^2=324 m$

We can also find the velocity of the car after these 20 seconds using the equation:

$v_1 = u +a_1 t_1 = 0 + (1.62)(20)=32.4 m/s$

Now we can find the distance covered by the car in the 2nd part, where it decelerates after having seen the tree limb on the road. We can do it by using the suvat equation:

$s_2 = (\frac{v_1 + v_2}{2})t_2$

where:

$v_1=32.4 m/s$ is the initial velocity at the beginning of the 2nd phase

$v_2=0$ is the final velocity (the car comes to a stop)

$t_2=5 s$ is the time elapsed in the 2nd phase

Substituting,

$s_2=\frac{32.4+0}{2}(5)=81 m$

So, the total displacement of the car is

$s=s_1+s_2=324+81=405 m$

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

3 0

3 years ago

How much heat is absorbed by 60 g of copper when it is heated from 20°C to 80°C?

ira [324]

Answer:

1,836J

Explanation:

6 0

3 years ago

to measure the static friction coefficient between a block and a vertical wall, a spring is attached to the block, is pushed on

Stolb23 [73]

Answer:

μ = mg/kx

Explanation:

Since the bock does not slip, the frictional force equals the weight of the block. So, F = mg. Now, the frictional force, F = μN where μ = coefficient of static friction and N = Normal force.

Now, the normal force equals the spring force F' = kx where k = spring constant and x = compression of spring.

N = F' = kx

So, F = μN = μkx

μkx = mg

So, μ = mg/kx

8 0

3 years ago

Maurice pulls on the end of a spring scale. He lets go of the end and observes the spring snap back into place. What force resto

andreev551 [17]

Elastic is the right answer.

3 0

3 years ago

Read 2 more answers