Answer:
Explanation:
maximum energy of capacitor
E = 1/2 C V ²
C is capacitance of capacitor and V is potential difference
given V = 88 V
E = 2002 x 10⁻⁶ J
Putting the values
2002 x 10⁻⁶ = 1/2 x C x 88²
C = .517 x 10⁻⁶ F .
In the second case
Energy E = 125 x 10⁻⁶ J .
C = .517 x 10⁻⁶
V = ?
E = 1/2 C V ²
125 x 10⁻⁶ = 1/2 x .517 x 10⁻⁶ x V²
V² = 483.55
V = 21.98 V .
Answer:
Explanation:
Impulse on an object is given by ![\mathrm{[impulse]}=F\Delta t](https://tex.z-dn.net/?f=%5Cmathrm%7B%5Bimpulse%5D%7D%3DF%5CDelta%20t)
.
However, it's also given as change in momentum (impulse-momentum theorem).
Therefore, we can set the change in momentum equal to the former formula for impulse:
.
Momentum is given by 
. Because the truck's mass is maintained, only it's velocity is changing. Since the truck is being slowed from 26.0 m/s to 18.0 m/s, it's change in velocity is 8.0 m/s. Therefore, it's change in momentum is:
.
Now we plug in our values and solve:
(two significant figures).
