Impulse = Change in momentum.
The ball was moving with a momentum of 0.45 * 22 = 9.9
The ball comes to rest in the receivers arm; this means the ball's final velocity = 0. So mv2 = 0.45 * 0
The magnitude of the impact is just the change in momentum. 9.9 - (0.45 * 0) = 9.9
G.P.E = mgh
Weight = mg = 200N
So G.P.E = 200 * 2 = 400 Joules
Both carts experience the same force but Cart A has a greater speed after the recoil.
The given parameters;
- <em>Mass of the cart A = 0.4 kg</em>
- <em>Mass of the cart B = 0.8 kg</em>
Apply the principle of conservation of linear momentum to determine the velocity of the carts after collision;

According to Newton's third law of motion, action and reaction are equal and opposite. The force exerted on cart A is equal to the force exerted on cart B but in opposite direction.

Thus, the correct statement that compares the motion and forces acting on the two carts is "Both carts experience the same force but Cart A has a greater speed after the recoil."
Learn more about conservation of linear momentum here: brainly.com/question/7538238