For the answer to the question above,
we can get the number of fringes by dividing (delta t) by the period of the light (Which is λ/c).
fringe = (delta t) / (λ/c)
We can find (delta t) with the equation:
delta t = [v^2(L1+L2)]/c^3
Derivation of this formula can be found in your physics text book. From here we find (delta t):
600,000^2 x (11+11) / [(3x10^8)^3] = 2.93x10^-13
2.93x10^-13/ (589x10^-9 / 3x10^8) = 149 fringes
This answer is correct but may seem large. That is because of your point of reference with the ether which is usually at rest with respect to the sun, making v = 3km/s.
Answer:
1. 0 vh g
Explanation:
As air resistance is negligible, horizontal speaking, nothing is affecting the velocity. So the horizontal velocity of the projectile stays the same, vh.
As for vertical velocity, since there's always a constant gravitational acceleration acting downward, namely g, the vertical speed will decrease until it reaches the top where it is 0, it then starting to increase in magnitude, downward, due to its gravitational acceleration g.
Answer: Permanent magnets consist of multiple "ferromagnetic materials" I think that might be the answer, there weren't really any choices for me to choose from.
What are the following statements? If there's one that mention a description of current action, or motion, that's your answer.
Ness awaits you sir, please be theoretical and positive eeeeeeeee
