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3 years ago

Covalent bonds usually occur between atoms that have

Chemistry

1 answer:

marta [7]3 years ago

7 0

Answer: A: high ionization energies; high electron affinitlies.

Explanation: Covalent bonds are basically about sharing of electrons between two atoms to achieve that stable structure. They are formed between two atoms when both have similar tendencies to attract electrons to themselves (i.e., when both atoms have identical or fairly similar ionization energies and electron affinities). Covalent bonding usually occurs between two non-metals.

For effective and proper bonding, the two atoms involved in the covalent bonding exercise should be small and hungry for electrons. This is to enable the nuclei of both atoms to effectively attract and hold the shared electron(s) in place; hence, the need for high ionization energies & high electron affinities for a more effective covalent bonding.

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What is unique about the way that transition metals form compounds?

Alika [10]

Answer:

<u><em>A. They don't form compounds</em></u>

Explanation:

High density: The strong bonding between the atoms in transition metals cause them to be tightly held together, creating a high density. Colored compounds: Transition metals tend to form more colored compounds than other elements, either in solid form or dissolved in a solvent.

4 0

3 years ago

Read 2 more answers

What would most likely happen to fish in a pond with low levels of dissolved oxygen?

MA_775_DIABLO [31]

It would probably die

7 0

4 years ago

Calculate the hydroxide ion concentration of a solution with pH=3.25. Show all calculations leading to an answer. NEED ASAP!! Pl

soldi70 [24.7K]

Answer:
[OH⁻] = 1.77 × 10⁻¹¹ M

Solution:
In order to calculate concentration of hydroxide ion i.e. [OH⁻] first we will find the pOH by using following relation,

pH + pOH = 14

Putting value of pH given and solving for pOH,

3.25 + pOH = 14

pOH = 14 - 3.25

pOH = 10.75

As ,
pOH = -log [OH⁻]
So,
[OH⁻] = 10^-pOH

Putting value of pOH,

[OH⁻] = 10⁻¹⁰·⁷⁵

[OH⁻] = 1.77 × 10⁻¹¹ M

3 0

3 years ago

The nucleoside adenosine exists in a protonated form with a pKa of 3.8. The percentage of the protonated form at pH 4.8 is close

Natasha_Volkova [10]

Answer:

Ok:

Explanation:

So, you can use the Henderson-Hasselbalch equation for this:

pH = pKa + log( $A^-/HA$ ) where A- is the conjugate base of the acid. In other words, A- is the deprotonated form and HA is the protonated.

We can solve that

1 = log( $A^-/HA\\$ ) and so 10 = $A^-/HA$ or 10HA = A-. For every 1 protonated form of adenosine (HA), there are 10 A-. So, the percent in the protonated form will be 1(1+10) or 1/11 which is close to 9 percent.

6 0

3 years ago

Ionic bonds are formed when valence electrons are _____ between ____ to form ____

Anastaziya [24]

Answer: transferred, atoms , ions

Explanation:

An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element and the element which accepts the electrons is known as electronegative element. This bond is formed between a metal and an non-metal.

For formation of an ionic compound, the metal lose electrons to form positively charged ions called as cations and non metals gain electrons to form negatively charged ions called as anions.

For example:

Sodium atom will loose one electron to gain noble gas configuration and form sodium cation with +1 charge.

$[Na^+]=1s^22s^22p^63s^0$

Chlorine atom will gain one electron to gain noble gas configuration and form chloride ion with -1 charge.

$[Cl^-]=1s^22s^22p^63s^23p^6$

5 0

4 years ago