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2 years ago

9

What element would a metal, like sodium, most likely combine with?

2 answers:

Zinaida [17]2 years ago

6 0

It would mostly combine with bromine to form NaBr.

Explanation:

Sodium bromide is an inorganic compound with the formula NaBr. It is a high-melting white. NaBr is generated by employing sodium hydroxide with hydrogen bromide. Sodium bromide can be employed as a reference of the chemical element bromine.

It ingests this by the transfer of valence electrons from sodium, which is 1, to the bromine atom, that is now an ion. Both ions draw towards each other and make this type of chemical bond.

OverLord2011 [107]2 years ago

5 0

The answer you are looking for is "bromine". Hope this helps!

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3 years ago

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2 years ago

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3 years ago

The atom with the same number of neutrons as 12C is 9Be. 11B. 13C. 14N.

julia-pushkina [17]

Answer : The atom with the same number of neutrons as $^{12}C$ is, $^{11}B$

Explanation :

The given atom is, $^{12}C$

Atomic mass number = 12

Atomic number = 6

Atomic number = Number of protons = Number of electrons = 6

Number of neutrons = Atomic mass number - Atomic number = 12 - 6 = 6

Now we have to determine the number of neutrons in the given options.

In atom, $^{9}Be$

Atomic mass number = 9

Atomic number = 4

Atomic number = Number of protons = Number of electrons = 4

Number of neutrons = Atomic mass number - Atomic number = 9 - 4 = 5

In atom, $^{11}B$

Atomic mass number = 11

Atomic number = 5

Atomic number = Number of protons = Number of electrons = 5

Number of neutrons = Atomic mass number - Atomic number = 11 - 5 = 6

In atom, $^{13}C$

Atomic mass number = 13

Atomic number = 6

Atomic number = Number of protons = Number of electrons = 6

Number of neutrons = Atomic mass number - Atomic number = 13 - 6 = 7

In atom, $^{14}N$

Atomic mass number = 14

Atomic number = 7

Atomic number = Number of protons = Number of electrons = 7

Number of neutrons = Atomic mass number - Atomic number = 14 - 7 = 7

Therefore, the atom with the same number of neutrons as $^{12}C$ is, $^{11}B$

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2 years ago