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Nastasia [14]
3 years ago
9

What element would a metal, like sodium, most likely combine with?

Chemistry
2 answers:
Zinaida [17]3 years ago
6 0

It would mostly combine with bromine to form NaBr.

Explanation:

Sodium bromide is an inorganic compound with the formula NaBr. It is a high-melting white. NaBr is generated by employing sodium hydroxide with hydrogen bromide. Sodium bromide can be employed as a reference of the chemical element bromine.

It ingests this by the transfer of valence electrons from sodium, which is 1, to the bromine atom, that is now an ion. Both ions draw towards each other and make this type of chemical bond.

OverLord2011 [107]3 years ago
5 0
The answer you are looking for is "bromine". Hope this helps!
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Which statement is incorrect?
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Answer:

e. When the indicator changes color and remains, 2 more drops of the solution in the buret should be added.

Explanation:

<em>Which statement is incorrect? </em>

<em>Select one: </em>

<em> a. The volume of solution in the buret should be recorded when the endpoint is reached. </em> CORRECT. At the endpoint, the titrant is expected to have completely reacted with the titrand.

<em>b. It is good practice to place the flask over a white background to better observe the color change of the solution.</em>  CORRECT. Using a white background makes it easier to detect the changes in the color of the indicator.

<em>c. The endpoint is when the indicator changes color.</em> CORRECT. This is the function of an indicator.

<em>d. Phenolphthalein will go from a colorless solution to a pink solution for the addition of NaOH to an acid solution.</em>  CORRECT. Phenolphthalein is colorless when pH < 8.3 and it is pink when pH > 10.0.

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3 years ago
If the molar heat of combustion of liquid benzene at constant volume and 300k is -3272KJ. Calculate the heat of combustion at co
vladimir2022 [97]

Answer:

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Explanation:

The combustion equation is 2C₆H₆ (l) + 15O₂ (g)  → 12CO₂ (g) + 6H₂O (l)

\Delta n_g = (12 - 15)/2 = -3/2

We have;

\Delta H = \Delta U + \Delta n_g\cdot R\cdot T

Where R and T are constant, and ΔU is given we can write the relationship as follows;

H = U + \Delta n_g\cdot R\cdot T

Where;

H = The heat at constant pressure

U = The heat at constant volume = -3,272 kJ

\Delta n_g = The change in the number of gas molecules per mole

R = The universal gas constant = 8.314 J/(mol·K)

T = The temperature = 300 K

Therefore, we get;

H = -3,272 kJ + (-3/2) mol ×8.314 J/(mol·K) ×300 K) × 1 kJ/(1000 J) = -3,275.7413 kJ

The heat at constant pressure, H = -3,275.7413 kJ.

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