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d1i1m1o1n [39]
2 years ago
7

Balance the chemical equation hcl+ Naoh

Chemistry
1 answer:
sattari [20]2 years ago
6 0

Answer:

NaCL + H2O

Explanation:

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Explanation needed please!
VashaNatasha [74]

Answer:

Below

Explanation:

2) there are 28 protons in this isotope

     The number that is on the bottom of the "stacked pair" tells you how many protons are in this isotope. It is often represented by the variable Z.

3) there are 35 neutrons in this isotope

     Subtract the number of protons (28) from the top number

4) there are 28 electrons in the neutral element of Nickel

     If you were to look at the period table and find Ni, you would see that its atomic number is 28. This number tells us the amount of protons and electrons there are in that element.

5) 62.9296694 atomic mass units

     Just search it up (unless your teacher wants you to calculate it)

6) there are 92 protons in this isotope

     Again just look at the Z value to find the proton count

7) there are 146 neutrons in this isotope

     Subtract 238 - 92 = 146

8) there are 92 electrons in the neutral element of uranium

     Again just look at the periodic table and find U

9) 238.0507882 atomic mass units

10) 12C or carbon 12 is more likely to bond with oxygen that 14c carbon 14

     This is because 12C is more abundant at 98.93% than 14C

Hope this helps! Best of luck <3

6 0
2 years ago
A mole of a substance has a mass in grams that is equal to the molecular mass. For example, a carbon atom has a mass of 12.01 u.
IRINA_888 [86]

Answer:

M(Fe₂O₃) = 159.70 g/mol

M(CO) = 28.01 g/mol

M(Fe) = 55.85 g/mol

M(CO₂) = 44.01 g/mol

Explanation:

We can calculate the molar mass of a compound by summing the molar masses of the elements that form it.

Fe₂O₃

M(Fe₂O₃) = 2 × M(Fe) + 3 × M(O) = 2 × 55.85 g/mol + 3 × 16.00 g/mol = 159.70 g/mol

CO

M(CO) = 1 × M(C) + 1 × M(O) = 1 × 12.01 g/mol + 1 × 16.00 g/mol = 28.01 g/mol

Fe

M(Fe) = 1 × M(Fe) = 1 × 55.85 g/mol = 55.85 g/mol

CO₂

M(CO₂) = 1 × M(C) + 2 × M(O) = 1 × 12.01 g/mol + 2 × 16.00 g/mol = 44.01 g/mol

3 0
3 years ago
Aqueous sulfuric acid (H2SO4) reacts with solid sodium hydroxide (NaOH) to produce aqeous sodium sulfate (Na2SO4) and liquid wat
Montano1993 [528]

Answer:

The theoretical yield of water formed is 2.2 grams

Explanation:

Step 1: Data given

Mass of H2SO4 = 5.9 grams

Mass of NaOH = 6.6 grams

Molar mass H2SO4 = 98.08 g/mol

Molar mass of NaOH = 40.0 g/mol

Step 2: The balanced equation

2NaOH + H2SO4 → Na2SO4 + 2H2O

Step 3: Calculate moles

Moles = mass / molar mass

Moles H2SO4 = 5.9 grams / 98.08 g/mol

Moles H2SO4 = 0.060 moles

Moles NaOH = 6.6 grams / 40.0 g/mol

Moles NaOH = 0.165 moles

Step 4: Calculate the limiting reactant

For 2 moles NaOH we need 1 mol H2SO4 to produce 1 mol Na2SO4 and 2 moles H2O

H2SO4 is the limiting reactant. It will completely be consumed ( 0.060 moles). NaOH is in excess . There will react 2*0.060 = 0.120 moles

There will remain 0.165 - 0.120 = 0.045 moles NaOH

Step 5: Calculate moles H2O

For 2 moles NaOH we need 1 mol H2SO4 to produce 1 mol Na2SO4 and 2 moles H2O

For 0.0600 moles H2SO4 we'll have 2*0.0600 = 0.120 moles H2O

Step 6: Calculate mass H2O

Mass H2O = 0.120 moles * 18.02 g/mol

Mass H2O = 2.16 grams

The theoretical yield of water formed is 2.2 grams

4 0
3 years ago
A solution has a<br> pH of 2.5.<br> Answer the following questions.<br> pOH =<br> [H]=<br> [OH]=
Sloan [31]

Answer:

pOH = 11.5

[H⁺] = 0.003 M

[OH⁻] = 3 × 10⁻¹² M

Explanation:

The computation is shown below:

Given that

pH = 2.5

Based on the above information

We know that

pH + pOH = 14  ⇒  pOH = 14 - pH

pOH = 14 - 2.5

pOH = 11.5

[H⁺] = 10^(-pH) = 10^(-2.5)

[H⁺] = 0.003 M

[OH⁻] = 10^(-pOH)

= 10^(-11.5)

= 3 × 10⁻¹² M

[OH⁻] = 3 × 10⁻¹² M

Hence, the above represents the answer

4 0
3 years ago
What evidence exists for a more recent increase in greenhouse gas concentrations in the atmosphere
TiliK225 [7]

Answer:

-data collected from Mauna Loa shows an increase in CO2 by 20% in the last 40 years

-ice core data shows links between CO2 and temperature, with a recent increase in both

-data from ice cores and other proxies show increases in CO2, CH4, and N2O since the Industrial Revolution

6 0
2 years ago
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