A golfer putted a golf ball 4.7 ft across a green. How many inches does this represent?

if you react 28 grams of butene with excess hydrogen how many grams of butane would you expect to get

liberstina [14]

Answer:

The correct answer is 29 grams.

Explanation:

Based on the given question, the reaction will be,

CH3CH=CHCH3 + H2 ⇒ CH3CH2CH2CH3

The molecular weight of butene is 56 grams per mole, and the molecular weight of butane is 58 grams per mole.

Thus, it can be said that 56 grams of butene reacts with hydrogen gas and produces 58 grams of butane.

Therefore, 28 grams of butene when reacts with hydrogen gas to give,

= 58/56 * 28 = 29 grams of butane.

Hence, the mass of butane produced will be 29 grams.

8 0

2 years ago

The temperature of a 95.4 g piece of Cu increases from 25.0 °C to 48.0 °C when the Cu absorbs 849 J of heat. What is the specifc

melisa1 [442]

<h3>Answer:</h3>

0.387 J/g°C

<h3>Explanation:</h3>

To calculate the amount of heat absorbed or released by a substance we need to know its mass, change in temperature and its specific heat capacity.
Then to get quantity of heat absorbed or lost we multiply mass by specific heat capacity and change in temperature.
That is, Q = mcΔT

in our question we are given;

Mass of copper, m as 95.4 g

Initial temperature = 25 °C

Final temperature = 48 °C

Thus, change in temperature, ΔT = 23°C

Quantity of heat absorbed, Q as 849 J

We are required to calculate the specific heat capacity of copper

Rearranging the formula we get

c = Q ÷ mΔT

Therefore,

Specific heat capacity, c = 849 J ÷ (95.4 g × 23°C)

= 0.3869 J/g°C

= 0.387 J/g°C

Therefore, the specific heat capacity of copper is 0.387 J/g°C

3 0

3 years ago

Determine the molality of a solution of methanol dissolved in ethanol for which the mole fraction of methanol is 0.135. Give you

Alja [10]

<u>Answer:</u> The molality of the solution is 0.11 m

<u>Explanation:</u>

We are given:

Mole fraction of methanol = 0.135

This means that 0.135 moles of methanol is present in 1 mole of a solution

Moles of ethanol = 1 - 0.135 = 0.865 moles

To calculate the mass for given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of ethanol = 0.865 moles

Molar mass of ethanol = 46 g/mol

$0.865mol=\frac{\text{Mass of ethanol}}{46g/mol}\\\\\text{Mass of ethanol}=(0.865mol\times 46g/mol}=39.79g$

To calculate the molality of solution, we use the equation:

$Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

Where,

$m_{solute}$ = Given mass of solute (methanol) = 0.135 g

$M_{solute}$ = Molar mass of solute (methanol) = 32 g/mol

$W_{solvent}$ = Mass of solvent (ethanol) = 39.79 g

Putting values in above equation, we get:

$\text{Molality of methanol}=\frac{0.135\times 1000}{32\times 39.79}\\\\\text{Molality of methanol}=0.106m\approx 0.11m$

Hence, the molality of the solution is 0.11 m

6 0

3 years ago

Can U help me fill in the blank pls !!

KonstantinChe [14]

Answer:

Molecules, arranged, cube

Explanation:

These are possible answers.

5 0

3 years ago

Read 2 more answers

Conditions for an experimental chemistry reaction require a temperature of 300 K. The temperature in the lab is 55 F. Which of t

OLga [1]

The suggested answers are for K=298 degrees and the nearest correct answer seems to be increase the room temperature by 22 degrees Fahrenheit. But by calculation, for 300 K, then convert 300k to degrees Celsius = 300-273.15=26.85 degrees celsius. Then convert the 26.85 to degrees F, so F=9/5C + 32= 48.33+32=80.33-55F (present room temperature)=25.33 degrees F to increase the room temperature by.

6 0

3 years ago

Read 2 more answers