<u>Answer:</u> The correct answer is Option d.
<u>Explanation:</u>
According to Lewis acid-base concept:
The substance which is donating electron pair is considered as Lewis base and the substance which is accepting electron pair is considered as Lewis acid.
For the given chemical reaction:
is accepting electron pair and is getting converted to 
. Thus, it is considered as Lewis acid.
present in CuO is a Lewis base because it is donating electron pair.
Thus, the correct answer is Option d.
It means that is it a sugar molecule
Taking into account the change of units, 21.8 in³ is equal to 0.357238 L.
<h3>Definition of rule of three</h3>
The rule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.
If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other) , the direct rule of three must be applied using the following formula, where a, b and c known data and x the variable to be calculated:
a ⇒ b
c ⇒ x
So: x= (c×b)÷ a
The direct rule of three is the rule applied in this case where there is a change of units.
<h3>in³ to liters</h3>
To perform in this case the conversion of units, you must first know that 1 in³ = 0.0163871 L. So, the rule of three can be used as follow: if 1 in³ is 0.0163871 L, 21.8 in³ equals how many L?
1 in³ ⇒ 0.0163871 L
21.8 in³ ⇒ x
So: x= (21.8 in³ ×0.0163871 L)÷ 1 in³
Solving:
<u><em>x= 0.357238 L</em></u>
In summary, 21.8 in³ is equal to 0.357238 L.
Learn more with this example:
brainly.com/question/12482948
#SPJ1
Answer:
Explanation:
Hello,
In this case, for the acid dissociation of formic acid (HCOOH) we have:
Whose equilibrium expression is:
![Ka=\frac{[H^+][HCOO^-]}{[HCOOH]}](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B%5BH%5E%2B%5D%5BHCOO%5E-%5D%7D%7B%5BHCOOH%5D%7D)
That in terms of the reaction extent is:
Thus, solving for 
which is also equal to the concentration of hydrogen ions we obtain:
![[H^+]=0.00528M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D0.00528M)
Then, as the pH is computed as:
![pH=-log([H^+])](https://tex.z-dn.net/?f=pH%3D-log%28%5BH%5E%2B%5D%29)
The pH turns out:
Regards.
