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notka56 [123]
3 years ago
8

The greeks were the first to use the term _____?

Chemistry
1 answer:
Paraphin [41]3 years ago
5 0
The greeks were first to use the term atom by the scientist Democritus which he defined as an indivisible and the simplest part of a substance. Neutron was discoverred by the scientist Chadwick, proton was discovered by Sir Ernest Rutherford.For this problem, answer is A.
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True or false an object must be in contact to exert a force
steposvetlana [31]

Answer:

False

Explanation:

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Fresh water that flows into an ocean is an estuary. True or False​
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An estuary is an area where a freshwater river or stream meets the ocean. So it’s true
4 0
4 years ago
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After the completion of a gas forming reaction, the column of water remaining in the collection flask was measured to me 55 mm h
baherus [9]

Answer:

The partial pressure of the gas produced by the reaction is 0.9187 atm

Explanation:

Given;

vapor pressure of water, \rho_w = 0.0313 atm

measured atmospheric pressure, P_{Total} = 0.950 atm

partial pressure of the gas produced by the reaction = ?

According to Dalton's law of partial pressure; total pressure is equal to sum of partial pressure of water vapor and gas produced.

P_{Total} = P_{gas} + P_{water}

P_{gas} = P_{Total} -P_{water}

P_{gas} = 0.95 - 0.0313

P_{gas} = 0.9187 atm

Therefore, the partial pressure of the gas produced by the reaction is 0.9187 atm

3 0
4 years ago
As the food burned,
Ulleksa [173]

Answer:

I don't get it is it even a question?

8 0
3 years ago
How many grams of hydrogen are needed to produce 1.80g of water according to this equation?
Nastasia [14]

Answer:

0.2g of hydrogen is needed to produce 1.80g of water

Explanation:

$H_{2}+O_{2} \to 2H_{2}O$

No. of moles of water$= \frac{Weight}{Molecular \, weight}$ \\

From given values,

Weight of water $=1.80g$

Molecular weight of water $=18g$

$\therefore$ No. of moles of water$=\frac{1.80}{18}=0.1 $

From equation, it is clear that 2 moles of water can be formed by 2 moles of $H_{2}$

Hence, 0.1 mole of water can be formed from 0.1 mole of $H_{2}$

Now,

No. of moles of $H_{2} = \frac{Weight}{Molecular \, weight}$

$\Rightarrow weight \,of\, H_{2}=No.\,of\,moles \times Molecular\,weight$\\ $=0.1 \times 2=0.2g$

8 0
3 years ago
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