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Scilla [17]
3 years ago
7

Carbon dioxide dissolves in water to form carbonic acid, which is primarily dissolved CO2. Dissolved CO2 satisfies the equilibri

um equation.
CO2(g) <----> CO2(aq) The acid dissociation constants listed in most standard reference texts for carbonic acid actually apply to dissolved CO2. K=0.032 M/atm
For a CO2 partial pressure of 4.4×10-4 atm in the atmosphere, what is the pH of water in equilibrium with the atmosphere?
Note: Since carbonic acid is primarily dissolved CO2, the concentration of H2CO3 can be taken as equal to that of dissolved CO2.
My online homework is due tonight and I am hopelessly lost on how to solve this problem. :(
Chemistry
1 answer:
Dvinal [7]3 years ago
6 0
C = pK 
<span>C = 4.4E-4*0.032 = about 1.41E-5 </span>

<span>H2CO3 ==> H^+ + HCO3^- </span>

<span>k1 = (H^+)(HCO3^-)/(H2CO3) </span>
<span>(H^+)= (HCO3^-) = x </span>
<span>(H2CO3) = 1.41E-5 </span>
<span>Solve for x = (H^+) and convert to pH. </span>
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