A roller coaster car starts at 6 m/s at the top of the hill at the 3 seconds latter at the bottom of the hill the roller coaster
car is going 72 m/s, what was the cars acceleration?
1 answer:
Answer:
22m/s
Explanation:
Step one:
Given data
Initial velocity of roller coster u= 6 m/s
Final velocity v= 72m/s
time t= 3 seconds
Required
We want to solve for the acceleration of the roller coster
Step two:
From the formula
acceleration= v-u/t
substitute
a= 72-6/3
a=66
/3
a= 22 m/s
The cars acceleration 22m/s
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