Explanation:
tilting it will raise the height of its center of gravity.
Answer:
5.65 times
Explanation:
60 db sound is equal to 60 phons sound when frequency is kept at 1000Hz.
But when the frequency of sound is changed to 100 Hz , according to equal loudness curves , the loudness level on phon scale will be 35 phons.
A decrease of 10 phon on phon- scale makes sound 2 times less loud
Therefore a decrease of 25 phons will make loudness less intense by a factor equal to 2²°⁵ or 5.65 less intense . Therefore intensity at 100 Hz
must be increased 5.65 times so that its intensity matches intensity of 60 dB sound at 1000 Hz frequency.
Answer:
The mass of the meter stick is 
Explanation:
Here since the meter stick is in equilibrium position its net torque and net force should be equal to zero
Since at the begging the meter stick is balanced at center of the meter stick that means its center of mass should be present at 
Now lets consider the later case where stick is balanced by two 5.12 g coins .
Here torque due to two coins = 
Torque due to weight of meter stick =
= 
where m = mass of the meter stick
Here
.
Upon equating we will be getting mass of the meter stick =
Answer:
The number of complete vibration or wave made in
one second is called frequency.