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Mariana [72]
3 years ago
8

An illustration of a ball sitting at the top of a hill of height labeled h Subscript 1 Baseline = 2 m. A the the bottom of the h

ill it levels off and the leveled surface is at a height labeled h Subscript 2 Baseline = .5 m. A ball is released from the top of a hill. How fast is the ball going when it reaches the base of the hill? Approximate g as 10 m/s2 and round the answer to the nearest tenth. m/s
Physics
2 answers:
lesya [120]3 years ago
7 0

Answer:

5.5 m/s

Explanation:

Right on Edge

IRISSAK [1]3 years ago
5 0

Answer:

5.5

Explanation:

edge 2021

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Coulombs law says that the force between any two charges depends on the amount of charges and distance between them. This force is directly proportional to the magnitude of the two charges and inversely proportional to the distance between them.

F=k\frac{|q_1| |q_2|}{r^2}

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case 1:

q_1=-e\\ q_2=+3e\\ r=100pm\\ \Rightarrow F=k\frac{|-e||3e|}{(100pm)^2}=3ke^2\times10^8

case 2

q_1=-e\\ q_2=+2e\\ r=100pm\\ \Rightarrow F=k\frac{|-e||2e|}{(100pm)^2}=2ke^2\times10^8

case 3:

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3 0
3 years ago
Read 2 more answers
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