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Lelu [443]
3 years ago
6

Kevlar is a synthetic polymer that was marketed for the first time in 1971. It is difficult to cut and does not shrink when expo

sed to cold temperature. It will not rust or corrode, and it can be immersed in water without being affected. Kevlar has low chemical reactivity and is an insulator. It is flame resistant and will not melt or soften at high temperatures. How could this negatively affect society? A) It will not chemically react to acid rain like many other materials. B) Tire companies will not sell as many tires since they would not fail as easily. C) It would be more difficult and costly to dispose since it does not naturally break down easily. D) Bullets will no longer be able to penetrate materials made of Kevlar as easily as other materials.
Chemistry
2 answers:
ohaa [14]3 years ago
6 0

Answer:

The correct option is C

Explanation:

The negative impact of kevlar in the society is that it can not just be disposed via conventional methods. It's resistance to flame and  and high temperature means burning it will not dispose it. Also, its water resistant property means kevlar will obstruct drainages if thrown in the drainage - because when it piles up, water will not be able to pass through it hence obstructing the flow of water. It being difficult to cut, with its low reactivity and it's non-corrosive property means it will be very difficult and expensive to dispose

lubasha [3.4K]3 years ago
3 0
C. because it doesn't break down without chemicals, so it would eventually just pile up.
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For the reaction KClO2⟶KCl+O2 KClO2⟶KCl+O2 assign oxidation numbers to each element on each side of the equation. K in KClO2:K i
frosja888 [35]

Answer:

Explanation:

The formula of the reaction:

            KClO₂ → KCl + O₂

To assign oxidation numbers, we have to obey some rules:

  1. Elements in an uncombined state or one whose atoms combine with one another to form molecules have an oxidation number of zero.
  2. The charge on simple ions signifies their oxidation number.
  3. The algebraic sum of all the oxidation number of all atoms in a neutral compound is zero. For radicals with charges, their oxidation number is the charge.

The oxidation number of K in KClO₂:

                                   K + (-1) + 2(-2) = 0

                                    K-5 = 0

                                    K = +5

The oxidation number of K in KCl:

                                K + (-1) = 0

                                K = +1

The oxidation number Cl in KClO₂ is -1

For Cl in KCl, the oxidation number is -1

For O in KClO₂, the oxidation number is (2 x -2) = -4

For O in O₂, the oxidation number is 0

K moves from an oxidation state of +5 to +1. This is a gain of electrons and K has undergone reduction. We then say K is reduced.

O moves from an oxidation state of -4 to 0. This is a loss of electrons and O has undergone oxidation. We say O is oxidized.

7 0
3 years ago
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Which organelle would be best represented by a refrigerator because it stores food and water?
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6 0
3 years ago
What season starts in the northern hemisphere as the suns direct rays strike the equator moving from the southern hemisphere to
laila [671]

Answer:

summer

Explanation:

3 0
3 years ago
What is the pH of a solution of 0.800 M KH2PO4, potassium dihydrogen phosphate?
Nookie1986 [14]
KH₂PO₄ hydrolyzes as;
H₂PO₄⁻ + H₂O ↔ H₃PO₄ + OH⁻
Let x amount of H₂PO₄⁻ has reacted with water then,
Kb₁ = [H₃PO₄][OH⁻] / [H₂PO₄⁻]
[H₂PO₄⁻] = 0.8-x M
Kb₁ = x² / (0.8 - x)
Given Ka₁ = 7.5 x 10⁻³
so Kb₁ = 1 x 10⁻¹⁴ / (7.5 x 10⁻³) = 1.33 x 10⁻¹²
From this information:
1.33 x 10⁻¹² = x² / 0.8
x = [OH⁻] = 1.03 x 10⁻⁶ M
pOH = - log (1.03 x 10⁻⁶) = 5.99
pH = 14 - pOH = 14 - 5.99 = 8.01 



3 0
3 years ago
Jason measures three values of density for his unknown. The values he obtains are: 1.019 g/mL 1.498 g/mL 1.572 g/mL What is the
jok3333 [9.3K]

<u>Answer:</u> The average of the densities of the given measurements is 1.363 g/mL

<u>Explanation:</u>

The equation used to calculate density of a substance is given by:

\text{Density of a substance}=\frac{\text{Mass of a substance}}{\text{Volume of a substance}}

We are given:

First measured value of density, d_1 = 1.019 g/mL

Second measured value of density, d_2 = 1.498 g/mL

Third measured value of density, d_3 = 1.572 g/mL

Putting values in above equation, we get:

\rho_{mix}=\frac{d_1+d_2+d_3}{3}

\rho=\frac{1.019+1.498+1.572}{3}\\\\\rho=1.363g/mL

Hence, the average of the densities of the given measurements is 1.363 g/mL

7 0
3 years ago
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