Answer:
v = 40 m / s
Explanation:
Let's use the expressions for accelerated motion
v = v₀ + a t
where vo is the initial velocity, at the acceleration and t is the time.
as the body starts from rest its initial velocity is zero
v = 0 + at
let's calculate
v = 8 5
v = 40 m / s
Answer:
d. 6.0 m
Explanation:
Given;
initial velocity of the car, u = 7.0 m/s
distance traveled by the car, d = 1.5 m
Assuming the car to be decelerating at a constant rate when the brakes were applied;
v² = u² + 2(-a)s
v² = u² - 2as
where;
v is the final velocity of the car when it stops
0 = u² - 2as
2as = u²
a = u² / 2s
a = (7)² / (2 x 1.5)
a = 16.333 m/s
When the velocity is 14 m/s
v² = u² - 2as
0 = u² - 2as
2as = u²
s = u² / 2a
s = (14)² / (2 x 16.333)
s = 6.0 m
Therefore, If the car had been moving at 14 m/s, it would have traveled 6.0 m before stopping.
The correct option is d
Answer:
what time does it start.
what do I need to join.
what are your expectations.
