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mrs_skeptik [129]
3 years ago
13

Question 13: Consider the strength of the Hβ absorption line in the spectra of stars of various surface temperatures. This is th

e amount of light that is missing from the spectra because Hydrogen electrons have absorbed the photons and jumped from level 2 to level 4. How do you think the strength of Hβ absorption varies with stellar surface temperature?
Chemistry
1 answer:
finlep [7]3 years ago
5 0

Answer:

The absorption and strength of the H-beta lines change with the temperature of the stellar surface, and because of this, one can find the temperature of the star from their absorption lines and strength. To better comprehend, let us look into the concept of the atom's atomic structure.  

Atoms possess distinct energy levels and these levels of energy are constant, that is, the temperature has no influence on it. However, temperature possesses an influence on the electron numbers found within these levels of energy. Therefore, to generate an absorption line of hydrogen in the electromagnetic spectrum's visible band, the electrons are required to be present in the second energy level, that is when it captivates a photon.  

Therefore, after captivating the photons the electrons jump from level 2 to level 4, which shows that there is an increase in the stellar surface temperature and at the same time one can witness a decline in the strength of the H-beta lines. In case, if the temperature of the surface increases too much, then one will witness no attachment of electron with the hydrogen atom and thus no H lines, and if the temperature of the surface becomes too low, then the electrons will stay in the ground state and no formation of H lines will take place in that condition too.  

Hence, to generate a very robust H line, after captivating photons the majority of the electrons are required to stay in the second energy level.  

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Answer:

So the answer is every day

Explanation:

Plants respire at all times of the day and night because their cells need a constant energy source to stay alive.

8 0
3 years ago
_________ is the movement of materials across a cell membrane using cellular energy.
Airida [17]

Answer:

active transport

Explanation:

passive transport does not involve energy

4 0
2 years ago
Based on the graph of US population and steel consumption, what could have led to the increase in steel consumption seen
polet [3.4K]

Answer:

A. Whenever the population has increased, steel consumption has increased as well.

Explanation:

Based on the graph of US population and steel consumption, what could have led to the increase in steel consumption seen  on the graph is that whenever the population has increased, steel consumption has increased as well.

A critical look at the graph, you will discover that the population and the steel consumption are moving upwards (i.e they are increasing). It's seen that as the population increases, steel consumption increases. This is true because as the population increases, people are building houses, more transportation systems that require steel are being manufactured, more household utensils that are steel products are being fabricated etc; therefore the consumption of steel increases.

6 0
3 years ago
How is n1 in the Rydberg equation related to the quantum number n in the Bohr model?
gavmur [86]

Alove you!nswer:

Explanation545):

3 0
3 years ago
When copper metal is added to nitric acid, the following reaction takes place
zlopas [31]

Answer:

The volume of NO₂ gas collected over water at 25.0 °C is 1.68 Liters.

Explanation:

Cu (s) + 4 HNO_3 (aq) \rightarrow Cu(NO_3)_2 (aq) + 2 H_2O (l) + 2 NO_2 (g)

Moles of copper = \frac{2.01 g}{63.55 g/mol}=0.03163 mol

According to reaction, 1 mol of copper gives 2 moles of nitrogen dioxide gas.

Then 0.03613 moles of copper will give:

\frac{2}{1}\times 0.03163 mol=0.06326 mol of nitrogen dioxide gas

Moles of nitrogen dioxide gas = n = 0.06326 mol

Pressure of the gas = P

P = Total pressure - vapor pressure of water

P = 726 mmHg - 23.8 mmHg = 702.2 mmHg

P = 0.924 atm (1 atm = 760 mmHg)

Temperature of the gas = T = 25.0°C =298.15 K

Volume of the gas = V

PV=nRT

V=\frac{0.06326 mol\times 0.0821 atm L/mol K\times 298.15 K}{0.924 atm}

V = 1.68 L

The volume of NO₂ gas collected over water at 25.0 °C is 1.68 Liters.

3 0
3 years ago
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