Answer:
a) 2NaOH+H2SO4→Na2SO4+2H2O2NaOH+H2SO4→Na2SO4+2H2O
b) Số phân tử NaOH : Số phân tử H2SO4 = 2:1
Số phân tử NaOH : Số phân tử Na2SO4 = 2:1
Số phân tử NaOH : Số phân tử H2O = 2:2
Explanation:
Answer:
34.8 moles of O
Explanation:
First we break down Al2(SO4)3 and look at SO4 only. In this compound, there are already 4 moles of O. Then you see that there are 3 moles of (SO4), meaning there are 3*4 moles of O = 12 moles in the entire compound. Then you look at the question, where it's asking for 2.9 moles of the entire Al2(SO4)3 compound, so you multiply 2.9*12 = 34.8 total moles of O.
Given :
Initial mass , a = 150 gm .
Half time ,
.
Final mass , x = 18.75 gm .
To Find :
The time taken to decay 18.75 gm .
Solution :
We know , time taken is given by :

Here , k is a constant given by :

Putting all given value in above equation :
We get :

Therefore , time taken is 6.94 hours .
Hence , this is the required solution .