The answer is : <span>Gravity draws an object towards its strongest point. The main things holding you back are air resistance and friction. As a hill gets steeper, you are more in line with the center of gravity, so it overcomes friction and you move faster. Eventually when you are moving vertically there is no friction other than air resistance itself. At this time you will accelerate at 32 feet per second every second until you either hit something or reach terminal velocity which is around 120 mph. Air resistance (on the Earth at least) will not allow you to travel any faster. Hope this Helped! Good Luck! :)</span>
Answer:
Explanation:
As we know that volume is given as
so it is given in liter as
now we have six pack of such volume
so total volume is given as
so its mass is given as
now the change in temperature is given as
now the heat given to the liquid is given as
Answer:
E = 9.4 10⁶ N / C
, The field goes from the inner cylinder to the outside
Explanation:
The best way to work this problem is with Gauss's law
Ф = E. dA = qint / ε₀
We must define a Gaussian surface, which takes advantage of the symmetry of the problem. We select a cylinder with the faces perpendicular to the coaxial.
The flow on the faces is zero, since the field goes in the radial direction of the cylinders.
The area of the cylinder is the length of the circle along the length of the cable
dA = 2π dr L
A = 2π r L
They indicate that the distance at which we must calculate the field is
r = 5 R₁
r = 5 1.3
r = 6.5 mm
The radius of the outer shell is
r₂ = 10 R₁
r₂ = 10 1.3
r₂ = 13 mm
r₂ > r
When comparing these two values we see that the field must be calculated between the two housings.
Gauss's law states that the charge is on the outside of the Gaussian surface does not contribute to the field, the charged on the inside of the surface is
λ = q / L
Qint = λ L
Let's replace
E 2π r L = λ L /ε₀
E = 1 / 2piε₀ λ / r
Let's calculate
E = 1 / 2pi 8.85 10⁻¹² 3.4 10-12 / 6.5 10-3
E = 9.4 10⁶ N / C
The field goes from the inner cylinder to the outside
