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Korvikt [17]
3 years ago
14

What is force? What creates it?

Physics
2 answers:
nika2105 [10]3 years ago
7 0

Answer:

its an interaction that can move an object; push or pull makes it or gravity, magnetism

Explanation:

its all in the answer

ivolga24 [154]3 years ago
7 0

Answer:

In physics, a force is any interaction that, when unopposed, will change the motion of an object. A force can cause an object withmass to change its velocity (which includes to begin moving from a state of rest), i.e., toaccelerate. 

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How many electrons will there be in 5 coulombs of charge?
zysi [14]
There's no physics or electronics to this question.
It's just arithmetic.

The last part of the question TELLS you how many 'coulombs per electron'.

If you just flip that fraction (divide ' 1 ' by it, take its reciprocal), then
you'll have 'electrons per coulomb',  and 5 of those will answer the question.

I got 31,250,000,000,000,000,000 .  I could be wrong.  You should check it.
7 0
3 years ago
Which correctly lists three main causes of deforestation?
ASHA 777 [7]
I think it’s A. Mining and logging are huge factors
4 0
3 years ago
Read 2 more answers
Which phrase describes the energy transformation that happens in a
weqwewe [10]

Answer:

Mechanical energy into electrical energy

Explanation:

8 0
3 years ago
A 12.6-kg monkey is hanging by one arm from a branch and swinging on a vertical circle. As an approximation, assume a radial dis
Zinaida [17]

Answer:

a)27.3N

b)150.78N

Explanation:

Having in mind the conservation of energy, as the monkey goes up (gaining potential gravitational energy) the kinetic energy must be reduced, so reducing the velocity of the monkey. So the maximum velocity will be at this lower point with a velocity of 1.36m/s

From this velocity and the radius we can calculate the angular velocity for the monkey center of mass:

w=\frac{1.36m/s}{0.853m} =1.594 /s

with this we can calculate the centripetal force magnitude:

F=m*w^{2} *r=12.6kg*(1.594/s)^{2} *0.853m=27.3N

On the mokey center of mass we have two opposite forces acting, the tension of the arm and the weight, in order for the monkey to continue swinging the resolt of this two forces must be equal to the centripetal force:

T-P=F=>T=F+P

T=27.3N+12.6kg*9.8m/s^{2}=150.78N

8 0
3 years ago
An ideal diatomic gas undergoes a cyclic process. In the first step, the gas undergoes an isothermal expansion from V1 to 3.00 V
sergey [27]

Answer:

Step 1

Work done = -9134.4 J

ΔQ = -9134.4 J

Step 2

ΔQ =  -3570.32 J = ΔU

W = 0

Step 3

The pdV work done = 3570.32 J

The Vdp work done = 11053.37 J

Heat transferred, ΔE = 0.

Explanation:

For diatomic gases γ = 1.4

Step 1

Where:

v₂ = 3.00·v₁

On isothermal expansion of an ideal gas by Boyle's law, we have;

p₁·v₁ = p₂·v₂ which gives;

p₁·v₁ = p₂×3·v₁

Dividing both sides by v₁, we have;

p₁= 3·p₂

p_2 = \dfrac{p_1}{3}

Hence, the pressure is reduced by a factor of 3

Work done =

n\cdot R\cdot T\cdot ln\dfrac{v_{f}}{v_{i}}

Where:

n = 1 mole  

R = 8.3145 J/(mole·K)

T = 1000 K we have

1 \times 8.3145 \times 1000 \times ln\left (\dfrac{1}{3}  \right ) = -9134.4 J

Step 2

The gas undergoes a constant volume decrease in pressure given by Charles law as follows;

\dfrac{p_2}{p3} = \dfrac{T_1}{T_3}

Whereby p₂ > p₃, T₁ will be larger than T₃

W = 0 for constant volume process

ΔQ = m×cv×ΔT = 1 × 3.97 × -900 = -3570.32 J = ΔU

Step 3

For adiabatic compression, we have;

\dfrac{p_3}{p_1} = \left (\dfrac{V_1}{V_3}  \right )^{\gamma }  = \left (\dfrac{T_3}{T_1}   \right )^{\frac{\gamma }{\gamma -1}}

Where:

T₁ = 1000 K

T₃ = 100 K

We have;

\left (\dfrac{V_1}{3\cdot V_1}  \right )^{\gamma }  = \left (\dfrac{100}{1000}   \right )^{\dfrac{\gamma}{\gamma -1}}

\left (\dfrac{1}{3} \right )  = \left (\dfrac{1}{10}   \right )^{\dfrac{1}{\gamma -1}}

log\left (\dfrac{1}{3} \right )  = {\dfrac{1}{\gamma -1}} \times log \left (\dfrac{1}{10}   \right )^

\gamma -1 =\dfrac{log \left (\dfrac{1}{10}   \right )}{ log\left (\dfrac{1}{3} \right )  }  {

∴ γ-1 = 2.096

γ = 3.096

The pdV work done =

m \times c_v \times (T_1 - T_3)

m×R/(γ - 1)×(T₁ - T₃) =

3.97×(1000 - 100) = 3570.32 J

The Vdp work done =

m \times c_p \times (T_1 - T_3)

c_p = k \times c_v = 3.096 \times 3.97 = 12.3  \, J/(mol\cdot K)

12.3×(1000 - 100) = 11053.37 J

Heat transferred, ΔE = 0.

8 0
3 years ago
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