1. electrostatic interactions
<span>3. van de waals interactions </span>
<span>4. hydrogen bonding </span>
An isotope has the same number of <em>protons</em> but a different number of <em>elec</em><em>tro</em><em>n</em><em>s</em><em> </em>than others atom of the same element
Answer:
The concentration of the pyridinium cation at equilibrium is 1.00×10⁻³ M
Explanation:
In water we have
C₅H₅NHBr + H₂O ⇒ C₅H₅NH+ + Br−
Pyridinium Bromide (C₅H₅NHBr) Dissociates Completely Into C₅H₅NH+ And Br− as such it is a strong Electrolyte.
Therefore the number of moles of positive ion produced per mole of C₅H₅NHBr is one
pH = - log [H₃O⁺] Therefore 10^-pH = [H₃O⁺] = concentration of C₅H₅NHBr
= 10⁻³ = 0.001M = concentration of C₅H₅NHBr
The concentration of C₅H₅NHBr is = 1.00×10⁻³ M to two places of decimal
The answer is a Roman numeral.
Ex:
1: I
2: II
3: III
4: IV
5: V
6: VI
7: VII
8: VIII
9: IX
10: X
Answer:
K ^+ , CO3 ^2-
Explanation:
The compound is potassium trioxocarbonate(IV).
It contains cation (potassium ion) and acid radical ( trioxocarbonate (IV) ion).
Since K is in group 1 of the periodic table, it loses one electron to form ion i.e K^1. trioxocarbonate IV ion has a charge of 2-.and so the ions of the compound are as shown in the answer above.
