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Semenov [28]
3 years ago
13

What mass of AlCl3 is dissolved in 330 cm if the concentration of the solution is 283gdm 3?​

Chemistry
1 answer:
nalin [4]3 years ago
8 0

Mass of AlCl₃ : 93.39 g

<h3>Further explanation</h3>

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

\large {\boxed {\bold {M ~ = ~ \dfrac {n} {V}}}

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

So to find the number of moles can be expressed as

n = V x M

the volume of the solution = 330 cm³=0.33 dm³

the concentration of the solution = 283 g/dm³

mass of AlCl₃ :

\tt mass=V\times M\\\\mass=0.33\times 283=93.39~g

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