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2 years ago

What mass of AlCl3 is dissolved in 330 cm if the concentration of the solution is 283gdm 3?

Chemistry

1 answer:

nalin [4]2 years ago

8 0

Mass of AlCl₃ : 93.39 g

<h3>Further explanation</h3>

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

$\large {\boxed {\bold {M ~ = ~ \dfrac {n} {V}}}$

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

So to find the number of moles can be expressed as

n = V x M

the volume of the solution = 330 cm³=0.33 dm³

the concentration of the solution = 283 g/dm³

mass of AlCl₃ :

$\tt mass=V\times M\\\\mass=0.33\times 283=93.39~g$

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Second, we assume that the participating moles are equal to the stoichiometric ratios because we do not know the amounts of the reagents.

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$molH_{2} O = 1mol N_{2} H_{4} } . \frac{4 mol H_{2} O}{2mol N_{2} H_{4} }. \frac{18\frac{g}{mol} H_{2} O}{1mol H_{2} O_} } . \frac{ 1 mol N_{2}H_{4} }{32,04\frac{g}{mol} N_{2} H_{4} }$

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Using $N_{2} O_{4}$ to form $H_{2} O$

$molH_{2} O = 1mol N_{2} O_{4} } . \frac{4 mol H_{2} O}{1mol N_{2} O_{4} }. \frac{18\frac{g}{mol} H_{2} O}{1mol H_{2} O_} } . \frac{ 1 mol N_{2}O_{4} }{92\frac{g}{mol} N_{2} O_{4} }$

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3 years ago

What mass of AlCl3 is dissolved in 330 cm if the concentration of the solution is 283gdm 3?​

What mass of AlCl3 is dissolved in 330 cm if the concentration of the solution is 283gdm 3?