Question

What mass of AlCl3 is dissolved in 330 cm if the concentration of the solution is 283gdm 3?​

Answer 1

Mass of AlCl₃ : 93.39 g

Further explanation

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

$\large {\boxed {\bold {M ~ = ~ \dfrac {n} {V}}}$

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

So to find the number of moles can be expressed as

n = V x M

the volume of the solution = 330 cm³=0.33 dm³

the concentration of the solution = 283 g/dm³

mass of AlCl₃ :

$\tt mass=V\times M\\\\mass=0.33\times 283=93.39~g$