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inessss [21]
3 years ago
9

PLEASE HELP and HURRY!!! I have a few minutes to turn it in

Mathematics
2 answers:
love history [14]3 years ago
8 0

Answer:

\Large \boxed{\mathrm{square: 15 \ meters}} \\\\ \Large \boxed{\mathrm{triangle: 20 \ meters}}

Step-by-step explanation:

The perimeter of a square is \sf P=4s, where s is the side length.

The perimeter of an equilateral triangle is \sf P=3a, where a is the side length.

The side length of the equilateral triangle is 5 more than the side length of the square.

\sf a = s+5

The perimeter of the square and equilateral triangle are equal.

\sf 4s=3(s+5)

Expanding brackets.

\sf 4s=3s+15

Subtracting 3s from both sides.

\sf s=15

The side length of the square is 15 meters.

\sf a=15+5 \\\\\\ a=20

The side length of the triangle is 20 meters.

Sliva [168]3 years ago
4 0

Answer:

The side of the square is 15m

The side of the triangle is 20m

Step-by-step explanation:

P square = 4s  where s is the side length

P triangle = 3 x where x is the side length

x = s+5

The perimeters are equal

4s = 3x

Replace x with s+5

4s = 3(s+5)

Distribute

4s = 3s+15

Subtract 3s from each side

4s-3s = 15

s = 15

The side of the square is 15

x =s+5

  =15+5

   = 20

The side of the triangle is 20

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Consider a population of size N = 100 with the three individual mutants with relative growth rate rA = 2, rB = 1.01, and rC = 0.
Salsk061 [2.6K]

Answer 1 / 25

Step-by-step explanation:

The probability that the first

of the three mutants will take over the population = 2 / 100

The probability that the second

of the three mutants will take over the population = 1.01 / 100

The probability that the third

of the three mutants will take over the population = 0.99 / 100

Therefore, the probability that each of the three mutants will take over the population = probability of the first,second or third = 2 / 100 + 1.01 / 100 + 0.99 / 100 = (2+1.01+0.99)/100 = 4 / 100 = 2/25

7 0
3 years ago
Find area plsssssssssssssssss ty
natka813 [3]

Answer:

1,200

Step-by-step explanation:

20 X 12 X 5 = 1,200

7 0
3 years ago
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Solve for x. Assume that lines are diameters?
Delicious77 [7]
360 - 20 + 2x = 360
340 + 2x = 360
2x = 20
x = 10
5 0
3 years ago
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Suppose that a box contains 6 cameras and that 3 of them are defective. A sample of 2 cameras is selected at random. Define the
mezya [45]

Answer: 1/5, 1/2, 0.

Step-by-step explanation:

given data:

no of cameras = 6

no of cameras defective = 3

no of cameras selected = 2

Let p(t):=P(X=t)

p(2)=m/n,

m=binomial(3,2)=3!/2!= 3

n=binomial(6,2)=6!/2!/4! = 15

p(3)= 3/15

= 1/5.

p(1)=m/n,

m=binomial(6,1)*binomial(2,2)=6!/1!/4!*2!/2!/0!= 7.5

n=binomial(6,2)= 15

p(2)= 7.5/15

= 1/2

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7 0
3 years ago
Read 2 more answers
DO NOT OVERLOOK THIS!!!!!!!!
zmey [24]
<h2>Answer:</h2>

<u>Area</u> = 2(1/2 × 5 × 5) + 20 × 10

= 2 × 12.5 + 200

= 25 + 200

= 225ft².

3 0
3 years ago
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