Answer:
0.426 L
Explanation:
Boyles law is expressed as p1v1=p2v2 where
P1 is first pressure, v1 is first volume
P2 is second pressure, v2 is second volume.
Given information
P1=96 kPa, v1=0.45 l
P2=101.3 kpa
Unknown is v2
Making v2 the subject from Boyle's law
Substituting the given values then
Therefore, the volume is approximately 0.426 L
From our physics class, we know that Work is a product of
Force and Displacement. The force must be the force in the same direction with
the displacement. So force and displacement must be parallel.
A. How much work in J does the string do on the boy if the
boy stands still?
Since we know that: Work = Force * Displacement
and in this case displacement is equal to zero, therefore
Work must also be equal to zero.
Work = 0
B. How much work does the string do on the boy if the boy
walks a horizontal distance of 11m away from the kite?
Now are given a displacement of 11 m which is a horizontal
distance. Therefore we must first calculate the horizontal component of force:
Fx = 4.5 N * cos 30
Fx = 3.897 N
So work is:
Work = 3.897 N * 11 m
<span>Work = 42.87 J ~ 43 J</span>
Explanation:
Period of a mass on a spring is:
T = 2π√(m/k)
T is directly proportional with the square root of m. So as the mass increases, the period increases.
Apply Gay-Lussac's law:
P/T = const.
P = pressure, T = temperature, the quotient of P/T must stay constant.
Initial P and T values:
P = 180kPa, T = -8.0°C = 265.15K
Final P and T values:
P = 245kPa, T = ?
Set the initial and final P/T values equal to each other and solve for the final T:
180/265.15 = 245/T
T = 361K