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goldfiish [28.3K]

3 years ago

9

A motorist inflates the tires of her car to a pressure of 180 kPa on a day when the temperature is -8.0° C. When she arrives at

her destination, the tire pressure has increased to 245 kPa. What is the temperature of the tires if we assume that the tires do not expand?

1 answer:

GuDViN [60]3 years ago

4 0

Apply Gay-Lussac's law:

P/T = const.

P = pressure, T = temperature, the quotient of P/T must stay constant.

Initial P and T values:

P = 180kPa, T = -8.0°C = 265.15K

Final P and T values:

P = 245kPa, T = ?

Set the initial and final P/T values equal to each other and solve for the final T:

180/265.15 = 245/T

T = 361K

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