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motikmotik
3 years ago
5

PLEASE HELP ME!!!!!!! SEE PICTURE!!!!

Mathematics
2 answers:
leonid [27]3 years ago
6 0
The first answer is correct .
Svetradugi [14.3K]3 years ago
5 0
The fist one is the answere.
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Please help me!!!!!!!!:(
horsena [70]

Answer:

24% chance

Step-by-step explanation:

First, find the total number of graduates in the table, that number is 2610, that will be your numerator.

You will look at the table for the total number of students, that is 10730, that will be the denominator.

Now divide the smaller number/numerator (2610) by the larger number/denominator (10730)

\frac{2610}{10730} = 0.2432432...

Then, multiply by 100 to get the percentage: 24.32432...%

Now, round to the nearest percentage: 24%


7 0
3 years ago
You operate a gaming website, www.mudbeast.net, where users must pay a small fee to log on. When you charged $4 the demand was 5
sertanlavr [38]
A) Demand function

price (x)          demand (D(x))

4                      540

3.50                  810

D - 540          810 - 540
----------- =  -----------------
x - 4               3.50 - 4

D - 540
----------- = - 540
x - 4

D - 540 = - 540(x - 4)

D = -540x + 2160 + 540

D = 2700 - 540x

D(x) = 2700 - 540x

Revenue function, R(x)

R(x) = price * demand = x * D(x)

R(x) = x* (2700 - 540x) = 2700x - 540x^2

b) Profit, P(x)

profit = revenue - cost

P(x) = R(x) - 30

P(x) = [2700x - 540x^2] - 30

P(x) = 2700x - 540x^2 - 30

Largest possible profit => vertex of the parabola

vertex of 2700x - 540x^2 - 30

When you calculate the vertex you find x = 5 /2

=> P(x) = 3345

Answer: you should charge a log-on fee of $2.5 to have the largest profit, which is $3345.




5 0
3 years ago
Pls help. Which of the following numbers represents
serious [3.7K]

Answer:

89percent

Step-by-step explanation:

i am not good at math but what ever

8 0
4 years ago
The amount of gasoline sold each month to customers at Bob's Exxon station in downtown Navasota is a random variable. This rando
swat32

Answer:

The probability that Bob will win that wonderful trip on the basis of his gasoline sales this month

P(X≥ 2800) = P(Z₁≥1.5) = 0.0768

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Mean of the Population (μ) = 2500 gallons

Standard deviation of the population (σ) =200 gallons

Let 'X' be a random variable in Normal distribution

Given X = 2800

Z = \frac{x-mean}{S.D} = \frac{2800-2500}{200} = 1.5

<u><em>Step(ii):-</em></u>

The probability that Bob will win that wonderful trip on the basis of his gasoline sales this month

P(X≥ 2800) = P(Z₁≥1.5)

                  = 0.5 - A(Z₁)

                 =  0.5 - A(1.5)

                 =   0.5 -0.4232    ( from normal table)

                = 0.0768

<u><em>Conclusion</em></u>:-

The probability that Bob will win that wonderful trip on the basis of his gasoline sales this month

P(X≥ 2800) = P(Z₁≥1.5) = 0.0768

               

3 0
3 years ago
Some help me please i have 9 questions
Lyrx [107]

awnser:

m<3=50

Step-by-step explanation:

seen in the picture if you need help let me know

5 0
3 years ago
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