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Aleks [24]
3 years ago
11

After school, several students skateboard at the nearby park. Your best friend, Erwin, is a good skateboarder and happens to fal

l when attempting a fancy trick. After falling, Erwin gets back up and starts repeating the trick over and over again. How would a cognitive psychologist interpret Erwin getting back up and repeating the trick many times?
Physics
1 answer:
Alchen [17]3 years ago
3 0

Answer:

A person who never gives up.

Explanation:

due to his passion for skateboarding he try's his never gives up until he will finally learns the trick.

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A dog sits 2.6 m from the center of a merry- go-round. a) If the dog undergoes a 1.7 m/s^2 centripetal acceleration, what is the
alexgriva [62]

Answer:

a) v= 2.1 m/s

b) ω = 0.807 rad/s

Explanation

Conceptual analysis :

The dog and the merry-go- round describes a circular motion, then, the following formulas apply :

a_{c} =\frac{v^{2} }{r} Formula (1)

v = ω *r   Formula (2)

Where:

a_{c} : Centripetal acceleration(m/s²)

v: linear speed or tangential (m/s)

r :  radius of the circle (m)

ω : angular speed ( rad/s)

Data

r= 2.6 m

a_{c} =  1.7 m/s²

Problem develpment

a) We replace data in the formula 1 to calculate the dog's linear speed(v):

a_{c} =\frac{v^{2} }{r}

1.7 =\frac{v^{2} }{2.6}

v^{2} =1.7*2.6 = 4.42

v=(\sqrt{4.42})\frac{m}{s}

v= 2.1 m/s

b)We replace data in the formula 2 to calculate the angular speed of the merry-go- round (ω).

v = ω *r

2.1 = ω *2.6

ω = 2.1/2.6

ω = 0.807 rad/s

6 0
3 years ago
In each cycle of its operation or refrigerator removes 17 J of heat from the inside of the refrigerator and releases 40 J of hea
Lubov Fominskaja [6]

Answer:

23 J

Explanation:

According to the law of conservation of energy, the total heat given off to the surroundings by a refrigerator is equal to the work done by the refrigerator and the heat removed from the inside of the refrigerator.

So we can write:

Q_{h} = W+Q_{c}

where

Q_{c} is the heat removed from the cold reservoir (the inside of the refrigerator)

W is the work  done

Q_{h} is the work released into the hot reservoir (the surroundings)

Here we have:

Q_c=+17 J (heat removed from the inside of the refrigerator)

Q_h=+40 J (heat released into the surroundings)

Solving the equation for W, we find the work done:

W=Q_h-Q_c=40-17=23 J

7 0
3 years ago
Two boxers are fighting. Boxer 1 throws his 5 kg fist at boxer 2 with a speed of 9 m/s.
Sladkaya [172]

Answer:

0.001 s

Explanation:

The force applied on an object is equal to the rate of change of momentum of the object:

F=\frac{\Delta p}{\Delta t}

where

F is the force applied

\Delta p is the change in momentum

\Delta t is the time interval

The change in momentum can be written as

\Delta p=m(v-u)

where

m is the mass

v is the final velocity

u is the initial velocity

So the original equation can be written as

F=\frac{m(v-u)}{\Delta t}

In this problem:

m = 5 kg is the mass of the fist

u = 9 m/s is the initial velocity

v = 0 is the final velocity

F = -45,000 N is the force applied (negative because its direction is opposite to the motion)

Therefore, we can re-arrange the equation to solve for the time:

\Delta t=\frac{m(v-u)}{F}=\frac{(5)(0-9)}{-45,000}=0.001 s

4 0
3 years ago
How long would it take for a sound impulse to travel through an aluminum rod 1,500 meters long?
NNADVOKAT [17]
<span>I believe the answer is 0.29.</span>
5 0
3 years ago
Read 2 more answers
How far can a mother push a 20.0 kg baby carriage, using a force of 62 N, if she can only do 2920 J of work? (Round to include t
alexgriva [62]
The mathematical definition of work (W) is force (F) multiplied by distance (x). In order to determine the distance for fixed force and work the above equation needs to be rearranged to make x the subject. The work divided by the force is equal to the distance. In this case the mother can push the baby carriage by a distance equal to 2920 divided by 62, which is 47.1 metres. 
5 0
4 years ago
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