A sphere of volume 1.20×10−3m3 hangs from a cable. When the sphere is completely submerged in water, the tension in the cable is
1 answer:
Answer:
B = 62.9 N
Explanation:
This is an exercise on Archimedes' principle, where the thrust force equals the weight of the liquid
B = ρ g V
write the equilibrium equation
T + B -W = 0
B = W- T (1)
use the density to write the weight
ρ = m / V
m = ρ V
W = ρ g V
substitute in 1
B = m g -T
B = g V - T
To finish the calculation, the density of the material must be known, suppose it is steel \rho_{body} = 7850 kg / m³
calculate
B = 7850 9.8 1.20 10⁻³ - 29.4
B = 92.3 - 29.4
B = 62.9 N
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Answer: Yes, it can be a single, ordinary star.
Explanation: To determine a mass of a star, we use the orbital speed formula, given by: v = , where
v is the speed;
G is a constant: G = 6.67*
M is mass of a massive object;
R is the distance between the object orbiting and the massive object;
The formula can be rewritten as:
First, we change R from light years to km:
1km=1.057*
R=
Calculating mass:
M =
M = 4.25* kg
A solar mass is the standard unit of mass. It is approximately 2*Kg and can be used for comparison: A single star cannot be more than 50 solar masses.
50 solar masses = 50*2* =
kg
Comparing the mass of the object with this parameter, we have
= 0.235.
= 2.35.
From this, we know that 50 solar masses is greater than the small, massive object found. So, this object can be a single, ordinary star.