You're off to a good start, now find the mass of H2O and put it under I mol,
then multiply 1 mol over the mass of H2O by 215 grams
For this you will need electronegativity(χ). χ(Ca)=1, χ(Cl)=3, χ(Fe)=1,8, χ(O)=3,5, χ(H)=2,1, χ(S)=2,5, χ(F)=4. then you calculate difference of electronegativity between 2 atoms, where is highest, that is higly polar bond. So it is Ca-O bond Δ<span>χ=2.</span>
Answer is: BaCO₃ (barium carbonate).
barium carbonate is white powder with low solubility in water, but good solubility in acids (<span>with the exception of sulfuric acid), because it forms solunle salts and carbonic acid (decomposes on carbon(IV) oxide and water).
For example if we add hydrochloric acid in barium carbonate:
BaCO</span>₃(s) + 2HCl(aq) → BaCl₂(aq) + H₂CO₃(aq).
Answer:
The correct answer will be "100.7 mL". The further explanation is given below.
Explanation:
The given values are:
Temperature,
ΔT = 1°C
Mass,
m = 70 kg
c = 3.480 J/Kg.K
Amount of released heat will be:
⇒
On putting the estimated values, we get
Let M will be the amount of evaporated water at the temperature of 37°C.
Required heat will be:
⇒
Now, Lost heat will be equal to the required amount of heat.
⇒
On applying cross-multiplication, we get
Now,
⇒
On putting the estimated values, we get
The number of moles of b2o3 that will be formed is determined as 4 moles.
<h3>
Limiting reagent</h3>
The limiting reagent is the reactant that will be completely used up.
4 b + 3O₂ → 2b₂O₃
from the equation above;
4 b ------------> 2 b₂O₃
2b ------------> b₂O₃
2 : 1
3O₂ -------------> 2b₂O₃
3 : 2
b is the limiting reagent, thus, the amount of b2o3 to be formed is calculated as;
4 b ------------> 2 moles of b2o3
8 moles -------> ?
= (8 x 2)/4
= 4 moles
Thus, the number of moles of b2o3 that will be formed is determined as 4 moles.
Learn more about limiting reactants here: brainly.com/question/14222359
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