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ella [17]
3 years ago
11

Which of the following is not true in regard to noble gases? A. These elements have full outermost shells. B. These elements are

found in the last column (Group 18) on the periodic table. C. These elements tend to be relatively inactive. D. These elements tend to gain or lose electrons easily
Chemistry
2 answers:
Pachacha [2.7K]3 years ago
8 0
<h2>Answer:</h2>

D. These elements tend to gain or lose electrons easily

<h2>Explanation:</h2>

The gases which are considered as Nobel are generally nonreactive. Truth be told, they are the least responsive components on the periodic table. This is on the grounds that they have a total valence shell. They tend to pick up or lose electrons rarely.

In 1898, Hugo Erdmann begat the expression “Nobel gas” to mirror the low reactivity of these components, similarly as the respectable metals are less receptive than different metals. These gases have high energies of ionization and immaterial electronegativities. These gases have low breaking points and are on the whole gases at room temperature.

Likurg_2 [28]3 years ago
5 0

Answer:

D.These elements tend to gain or lose electrons easily is <em>incorrect.</em>

Explanation:

Noble gasses consist of atoms that have full rings of electrons. Electrons are what bond atoms together to create chemical compounds, and incomplete rings are needed for the process.

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Which element is reduced in the following reaction: 2Mg+O₂ → 2MgO if Mg goes from 0 to +2 and O goes from 0 to -2?
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Answer:

O.

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<em> O goes from 0 to -2, so, it is the element that is reduced.</em>

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3 years ago
When 2 molecules collide, what happens
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4 0
3 years ago
A mixture of0.161 moles of C is reacted with 0.117 moles of O2 in a sealed, 10.0 L-vessel at 500.0 K, producing a mixture of CO
labwork [276]

Answer:

number of moles of CO2 is 0.054

number of moles of CO is 0.107

number of moles of O2 remaining is 0.01 mole

mole fraction of CO is 0.63

Explanation:

Firstly, we write the equation of reaction;

3C(s) +2O2(g) → CO2(g) +2CO(g)

Now, we proceed.

From the written equation, we can deduce that

3 mol C = 2 mol O2 = 1 mol CO2 = 2 mol CO

No of mol of C reacted = 0.161 mol

limiting reactant according to the question is Carbon

a. no of mol of CO2 formed = 0.161*1/3 = 0.054 moles ( no of moles of CO2 formed is one-third of no of moles of carbon reacted. This is obtainable from their mole ratio 1:3)

b. no of mol of CO formed = 0.161*2/3 = 0.107 mol

c. no of mol of O2 remaining = 0.117 - (0.151*2/3) = 0.117-0.107 = 0.01 mole

d. mole fraction of CO = no of mol of CO/Total number of moles

= 0.107/(0.107+0.054+0.01)

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