Answer:
the answer I think is C I don't know for sure tho
Answer:
1. 3.70 g Na₂CO₃·10H₂O
2. 50.0 mL of the first solution
Explanation:
1. Prepare the solution
(a) Calculate the molar mass of Na₂CO₃·10H₂O

The molar mass of Na₂CO₃·10H₂O is 286.15 g/mol.
(b) Calculate the moles of Na₂CO₃·10H₂O

(c) Calculate the mass of Na₂CO₃·10H₂O

2. Dilute the solution
We can use the dilution formula to calculate the volume needed.
V₁c₁ = V₂c₂
Data:
V₁ = ?; c₁ = 0.0500 mol·L⁻¹
V₂ = 100 mL; c₂ = 0.0250 mol·L⁻¹
Calculation:

Answer:
<u>49 moles of atoms</u>
Explanation:
There are 7 individual atoms in each molecule of H2SO4: (2 hydrogens + 1 sulfur + 4 oxygens).
Therefore, if 7 moles are decomposed, there would be 7 times that amount of individual atoms:
7 x 7 = 49 moles of atoms
Answer:
15 moles of ammonium sulfate would be formed from 30 moles of ammonia.
Explanation:
Given data:
Number of moles of ammonium sulfate formed = ?
Number of moles of ammonia = 30.0 mol
Solution:
Chemical equation:
2NH₃ + H₂SO₄ → (NH₄)₂SO₄
Now we will compare the moles of ammonium sulfate with ammonia.
NH₃ : (NH₄)₂SO₄
2 : 1
30.0 : 1/2×30.0 = 15.0 mol
So 15 moles of ammonium sulfate would be formed from 30 moles of ammonia.