Question

The pressure on a 200-milliliter sample of CO2(g) at

Answer 1

Answer:

A) 100 mL

Explanation:

At constant temperature and number of moles, Using Boyle's law  

${P_1}\times {V_1}={P_2}\times {V_2}$

Given ,  

V₁ = 200 mL

V₂ = ?

P₁ = 60 kPa

P₂ = 120 kPa

Using above equation as:

${P_1}\times {V_1}={P_2}\times {V_2}$

${60\ kPa}\times {200\ mL}={120\ kPa}\times {V_2}$

${V_2}=\frac{{60}\times {200}}{120}\ mL$

${V_2}=100\ mL$