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3 years ago

The pressure on a 200-milliliter sample of CO2(g) at

Chemistry

1 answer:

motikmotik3 years ago

3 0

Answer:

A) 100 mL

Explanation:

At constant temperature and number of moles, Using Boyle's law

${P_1}\times {V_1}={P_2}\times {V_2}$

Given ,

V₁ = 200 mL

V₂ = ?

P₁ = 60 kPa

P₂ = 120 kPa

Using above equation as:

${P_1}\times {V_1}={P_2}\times {V_2}$

${60\ kPa}\times {200\ mL}={120\ kPa}\times {V_2}$

${V_2}=\frac{{60}\times {200}}{120}\ mL$

${V_2}=100\ mL$

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Calculate the standard enthalpy change for the reaction at 25 ∘ C. Standard enthalpy of formation values can be found in this li

meriva

Answer:

The standard enthalpy change for the reaction at $25^{0}\textrm{C}$ is -2043.999kJ

Explanation:

Standard enthalpy change ( $\Delta H_{rxn}^{0}$ ) for the given reaction is expressed as:

$\Delta H_{rxn}^{0}=[3mol\times \Delta H_{f}^{0}(CO_{2})_{g}]+[4mol\times \Delta H_{f}^{0}(H_{2}O)_{g}]-[1mol\times \Delta H_{f}^{0}(C_{3}H_{8})_{g}]-[5mol\times \Delta H_{f}^{0}(O_{2})_{g}]$

Where $\Delta H_{f}^{0}$ refers standard enthalpy of formation

Plug in all the given values from literature in the above equation:

$\Delta H_{rxn}^{0}=[3mol\times (-393.509kJ/mol)]+[4mol\times (-241.818kJ/mol)]-[1mol\times (-103.8kJ/mol)]-[5mol\times (0kJ/mol)]=-2043.999kJ$

4 0

2 years ago

Carlos has a 1.2 meter long piece of wood. He wants to cut it into 3 equal lengths. How long should each piece be in millimeters

zhenek [66]

There are 1,000 mm in a meter so times 1.2 by 1,000 and you get 1,200.
Now since he wants it in three equal pieces divide 1,200/3 and you get 400.
So your answer is: 400 mm

6 0

2 years ago

You do an experiment in which you need 0.5 moles of tyrosine (C9H11NO3). How many grams must you weigh out?

Yuki888 [10]

Answer: a) 90.5g

b) 33.6 L

Explanation:-

Molar mass of tyrosine $(C_9H_{11}NO_3)$ = 181 g/mol

According to Avogadro's law, 1 mole of every substance weighs equal to its molar mass.

1 mole of tyrosine $(C_9H_{11}NO_3)$ weighs = 181 g/mol

0.5 moles of tyrosine $(C_9H_{11}NO_3)$ weigh $=\frac{181g/mol}{1}\times 0.5moles=90.5g$

b) According to Avogadro's law, 1 mole of an ideal gas occupies 22.4 Liters at Standard conditions of temperature and pressure (STP).

1 mole of gas at STP occupy = 22.4 L

1.5 moles of gas at STP occupy = $\frac{22.4L}{1}\times 1.5=33.6L$

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2 years ago

A student has 100. mL of 0.400 M CuSO4(aq) and is asked to make 100. mL of 0.150 M CuSO4(aq) for a spectrophotometry experiment.

ValentinkaMS [17]

Answer:

a. 37.5 mL

b. See the description below

Explanation:

a. Volume of 0.400 M CuSO₄(aq) required for the preparation

In dissolutions, since the number of moles of solute is constant, the equation is:

$C_1\times V_1=C_2\times V_2$

Substitute and solve for V₁

$0.400M\times V_1=0.150M\times 100ml$

$V_1=0.150M\times 100.ml/0.400M=37.5ml$

b. Briefly describe the essential steps to most accurately prepare the 0.150 M CuSO₄(aq) from the 0.400 M CuSO₄(aq)

You will use the stock solution, the funnel, the buret, and distilled water.

i) Using the funnel, fill in the buret with with 50 ml of the stock solution, i.e. the 100. ml of 0.400 M CuSO₄(aq) solution.

ii) Pour 37.5 ml of the stock solution from the burete into the volumetric flask.

iii) Carefully add disitlled water to the 37.5ml of the stock solution in the volumetric flask until the mark (50 ml) on the volumetric flask.

iv) Put the stopper and rotate the volumetric flask to homegenize the solution.

3 0

3 years ago

How did geologist find out that the ash in Idaho is the same ash in Nebraska

Zolol [24]

Answer:

Only a volcano could have produced so much ash, but there are NO volcanoes in Nebraska, where the animals were found. One Geologist in Idaho knew of a volcanic eruption dating from the same time.Bill Bonnichsen tied the 2 events together using dating techniques and comparing the ash composition from a supervolcano called Bruneau Jarbridge.

3 0

2 years ago