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icang [17]
3 years ago
6

Which Of These Periods Contain Elements With Electrons s,p,d and f orbitals? Periods 1-3 Periods 1-4

Chemistry
1 answer:
Elanso [62]3 years ago
7 0
The answer would be periods 6-7 :)
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A chemist has a small amount of compound ( b.p. = 65 oC) that must be fractionally distilled. Yet, the Chemist does not want to
koban [17]

Answer:

The chemist can either:

a. Use a small fractionation apparatus.

b. Add a compound with a much higher boiling point.

Explanation:

Using a smaller fractionation apparatus or Vigreux column will help to minimize loss of the distillate.

If a compound with a higher boiling point is added, the vapors of this liquid will displace the vapors of this small amount of compound with a lower boiling point. This compound with a higher boiling point is known as a Chaser.

6 0
3 years ago
I NEED HELP PLEASE, THANKS! :)
TEA [102]

Answer:

K=\frac{[CaO][CH_{4}][H_{2}O ]^{2}  }{[CaCO_{2}][H_{2}]^4  }

Explanation:

The equilibrium expression is the K value equal to the product of the concentrations of the products over the product of the concentrations of the reactants.  If there is a coefficient in front of the compound, raise the molecule to that power.

Since K is big, more product is expected.  This is because of mathematic principles.  A large numerator with a small denominator will produce a large number.

3 0
3 years ago
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An alpha particle is equivalent to a _____ nucleus.
astra-53 [7]
Alpha particle is equivalent to B. Helium atom (2 protons, 2 neutrons) 
6 0
3 years ago
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The factor that affects how easily an electron can be removed from an atom is the
Zolol [24]

Answer: D

Explanation:

The answer is D

4 0
3 years ago
How do you work out question 1a?
Sliva [168]

Answer:

-125 kJ

Explanation:

You calculate the energy required to break all the bonds in the reactants. Then you subtract the energy to break all the bonds in the products.

                     H₂C=CH₂   +    H₂ ⟶    H₃C-CH₃

Bonds:       4C-H + 1C=C     1H-H     6C-H + 1C-C

D/kJ·mol⁻¹:  413       612        436       413      347

The formula relating ΔHrxn and bond dissociation energies (D) is

ΔHrxn = Σ(Dreactants) – Σ(Dproducts)

(Note: This is an exception to the rule. All other thermochemical reactions are “products – reactants”. With bond energies, it’s “reactants – products”. The reason comes from the way we define bond energies.)

<em>For the reactant</em>s:

Σ(Dreactants) = 4 × 413 + 1 × 612 + 1 × 436 = 2700 kJ

<em>For the products:</em>

Σ(Dproducts) = 6 × 413 + 1 × 347 = 2825 kJ

<em>For the system</em> :

ΔHrxn = 2700 - 2825 = -125 kJ

4 0
3 years ago
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