How many grams of calcium chloride are dissolved in 5.65 liters of a 0.11 m solution of calcium choride?

1 answer:

4 0

C = 0.11 mol
V = 5.65 L
n = ???

n = C*V
n = 0.11 * 5.65
n = 0.622 mols

1 mol of CaCl2 = 40 + 2*35.5 = 111 grams
0.622 mol = x

x = 111 * 0.622
x = 69.0 grams CaCl2

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