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yuradex [85]
3 years ago
9

What is the period of wave if the wavelength is 100m and the speed is 200m/s

Physics
1 answer:
Anna11 [10]3 years ago
6 0

Answer:

50m/s

Explanation:

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The nucleus of an atom can be modeled as several protons and neutrons closely packed together. Each particle has a mass of 1.67
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Explanation:

The nucleus of an atom can be modeled as several protons and neutrons closely packed together.

Mass of the particle, m=1.67\times 10^{-27}\ kg

Radius of the particle, R=10^{-15}\ m

(a) The density of the nucleus of an atom is given by mass per unit area of the particle. Mathematically, it is given by :

d=\dfrac{m}{V}, V is the volume of the particle

d=\dfrac{m}{(4/3)\pi r^3}

d=\dfrac{1.67\times 10^{-27}}{(4/3)\pi (10^{-15})^3}

d=3.98\times 10^{17}\ kg/m^3

So, the density of the nucleus of an atom is 3.98\times 10^{17}\ kg/m^3.

(b) Density of iron, d'=7874\ kg/m^3

Taking ratio of the density of nucleus of an atom and the density of iron as :

\dfrac{d}{d'}=\dfrac{3.98\times 10^{17}}{7874}

\dfrac{d}{d'}=5.05\times 10^{13}

d=5.05\times 10^{13}\ d'

So, the density of the nucleus of an atom is 5.05\times 10^{13} times greater than the density of iron. Hence, this is the required solution.

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4 years ago
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Explanation:

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4 0
3 years ago
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Explanation:

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A rocket is launched with a velocity of 30 m/s at 40° to the horizontal. How far will it travel horizontally? 0 3.01 m 0 90.54 m
Lapatulllka [165]

Answer:

The horizontal distance traveled by the rocket is 90.46 m

Explanation:

Given;

initial velocity of the rocket, u = 30 m/s

angle of projection, θ = 40°

the horizontal distance traveled by the rocket = ?

The horizontal distance traveled by the rocket is given by the range of the projectile.

The range of the projectile is given as;

R = \frac{u^2Sin(2\theta)}{g}\\\\R = \frac{(30)^2sin(80^0)}{9.8}\\\\R = 90.46 \ m

Therefore, the horizontal distance traveled by the rocket is 90.46 m

The closest answer in the given options is 90.54 m

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