-- The two 8-ohm resistors in parallel are equivalent to
a single 4-ohm resistor.
-- The current in the circuit is
(voltage) / (resistance) = (9v) / (4ohms) = 2.25 Amperes
-- If another resistor is added in parallel, then no matter how large
or small it is, the current in the circuit increases.
(When another lane is added to a road, the traffic capacity of the
road increases.)
The circuit is now equivalent to a 12.5-ohm resistor in parallel
with 4-ohms. That's ...
(12.5 x 4) / (12.5 + 4) = 50/16.5 = 3.03 ohms .
-- The new current is (9v) / (3.03 ohms) = 2.97 Amperes
Answer:
hhmmmmmhmmmm hmhmmmm hmmm yeah i got nothing
Explanation:
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The current in the second wire is 1.37 A.
<h3>Current in the second wire</h3>
The current in the second wire is calculated from the magnetic force between the two wires.
F/L = (μI₁I₂)/(2πr)
where;
- μ is permeability of free space
- I₂ is current in the second wire
- F/L is force per unit length
- r is the distance between the two wires
μI₁I₂ = (F/L 2πr)
I₂ = ((F/L 2πr) / (μI₁)
I₂ = (7.7 x ⁻⁵ x 2π x 0.082)/(4π x 10⁻⁷ x 23)
I₂ = 1.37 A
Thus, the current in the second wire is 1.37 A.
Learn more about current here: brainly.com/question/25537936
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