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Iteru [2.4K]
3 years ago
12

Please help with this

Physics
1 answer:
DanielleElmas [232]3 years ago
7 0

Answer:

D

Explanation:

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How many seconds will elapse between seeing lightning and hearing the thunder if the lightning strikes 1mi (5280 ft) away and th
alexandr1967 [171]

Answer:

t = 4.58 s

Explanation:

In this problem, we need to find the time elapse between seeing lightning and hearing the thunder if the lightning strikes 1mi (5280 ft) away and the air temperature is 90.0°F.

T = 90.0°F = 32.2 °C

The speed of sound at temperature T is given by :

v = (331.3 +0.6T)

Put T = 32.2°C

So,

v = (331.3 +0.6(32.2))

= 350.62 m/s

We have, distance, d = 1 mile = 1609.34

So,

t=\dfrac{d}{v}\\\\t=4.58\ s

So, the required time is equal to 4.58 seconds.

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3 years ago
What is the average reaction time of people
Yanka [14]

Answer:

the average reaction time is 0.25 seconds.

6 0
3 years ago
Read 2 more answers
A cat chase a mouse across a 1.0 m high table. The mouse steps out of the way, and the car slides off the table and strikes the
Tema [17]

The cat fell 1.0 m from the ground.

Using the formula

h = v_{oy}t - \frac{gt^2}{2}

Here, v_{oy} = 0, \; h = 1.0 \; m.

Solving for t, the time it spent in the air is

t = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2(1.0 \; m)}{9.8 \; m/s^2}} = 0.451753951 \; s

The cat does not accelerate along the horizontal, so it has constant horizontal velocity. Since it strikes the floor 2.2 m from the table, then

v_x = \Delta x/t = \frac{2.2\; m}{0.451753951 s} = 4.869907597 \; m/s \Rightarrow 4.9 \; m/s


5 0
3 years ago
A soccer ball is kicked from the ground with an initial speed v at an upward angle θ. A player a distance d away in the directio
Nady [450]

Answer:

The speed of player is given by

V=\frac{2v^{2} 2sin\alpha.cos\alpha-gd }{2vsin\alpha}

Explanation:

The time of flight for a projectile motion is given by

T=\frac{2vsin\alpha }{g}    (i)

where t is the time of flight, v is the initial speed, and α is the angle.

Now the person must also reach the impact point of ball in the same time as above.

Now the total distance D the player needs to cover is basically R horizontal range of projectile minus the distance d, range R is given by,

R=\frac{2v^{2} sin2\alpha }{g}

Now the distance the player must cover is given by

D= R-d

D= \frac{2v^{2} sin2\alpha }{g}  - d

 

D=\frac{2v^{2}sin2\alpha-gd}{g}  (ii)

Now the average speed of player is given by

V=\frac{D}{T}   (iii)

Replacing the values of D and T from eq. (i) and (ii) in eq. (iii).

V=\frac{\frac{2v^{2} sin2\alpha-gd }{g}}{\frac{2vsin\alpha }{g} }

V=\frac{2v^{2} 2sin\alpha.cos\alpha-gd }{2vsin\alpha}

3 0
3 years ago
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