Question

A rocket is launched with a velocity of 30 m/s at 40° to the horizontal. How far will it travel horizontally? 0 3.01 m 0 90.54 m 120 m O 141.39 m​

Answer 1

Answer:

The horizontal distance traveled by the rocket is 90.46 m

Explanation:

Given;

initial velocity of the rocket, u = 30 m/s

angle of projection, θ = 40°

the horizontal distance traveled by the rocket = ?

The horizontal distance traveled by the rocket is given by the range of the projectile.

The range of the projectile is given as;

$R = \frac{u^2Sin(2\theta)}{g}\\\\R = \frac{(30)^2sin(80^0)}{9.8}\\\\R = 90.46 \ m$

Therefore, the horizontal distance traveled by the rocket is 90.46 m

The closest answer in the given options is 90.54 m