Answer: what are the answers to the questions
Explanation:
Answer ; The correct answer is : 346 m/s .
Sound is a type of longitudinal wave , which is produced when a matter compress or refracts .
Speed of sounds depends on factors like medium , density , temperature etc .
Effect of Temperature on speed of sounds :
When the temperature increases , molecules gains energy and they starts vibrating and with higher temperature vibration becomes fast . So the waves of sounds can travel faster due to faster vibrations . Hence , speed of sounds is directly proportional to the temperature or speed of sounds increases with increase in temperature .
The speed of sounds at 0⁰C is 331 ![\frac{m}{s}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bm%7D%7Bs%7D%20%20)
The relation between speed of sound and temperature is given as :
![V = 331 \frac{m}{s} + ( 0.6 \frac{m}{s- ^0C} * T )](https://tex.z-dn.net/?f=%20V%20%3D%20331%20%5Cfrac%7Bm%7D%7Bs%7D%20%20%2B%20%28%200.6%20%5Cfrac%7Bm%7D%7Bs-%20%5E0C%7D%20%2A%20T%20%20%29%20)
Given : Temperature = 25 ⁰ C
Plugging values in formula =>
![V = 331 \frac{m}{s} + (0.6 \frac{m}{s-^0C} * 25^0C)](https://tex.z-dn.net/?f=%20V%20%3D%20331%20%5Cfrac%7Bm%7D%7Bs%7D%20%2B%20%280.6%20%5Cfrac%7Bm%7D%7Bs-%5E0C%7D%20%20%2A%2025%5E0C%29%20%20%20)
![V = 331 \frac{m}{s} + 15 \frac{m}{s}](https://tex.z-dn.net/?f=%20V%20%3D%20331%20%5Cfrac%7Bm%7D%7Bs%7D%20%2B%2015%20%5Cfrac%7Bm%7D%7Bs%7D%20%20%20)
![V = 346 \frac{m}{s}](https://tex.z-dn.net/?f=%20V%20%3D%20%20346%20%5Cfrac%7Bm%7D%7Bs%7D%20%20)
Answer:
Cathode rays are streams of electrons observed in discharge tubes. In 1897, British physicist J. J. Thomson showed that cathode rays were composed of a previously unknown negatively charged particle, which was later named the electron. Cathode-ray tubes (CRTs) use a focused beam of electrons deflected by electric or magnetic fields to render an image on a screen.
Answer:
10.5L
Explanation:
The volume in this question can be calculated by using the formula for gas law equation as follows:
PV = nRT
Where;
P = pressure (atm)
V = volume (litres)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (K)
According to the provided information in this question:
P = 6.18 atm
V = ?
n = 2.35 moles
R = 0.0821 Latm/molK
T = 63°C = 63 + 273 = 336K
Using PV = nRT
V = nRT/P
V = 2.35 × 0.0821 × 336/ 6.18
V = 64.83/6.18
V = 10.49
V = 10.5L
Answer:
The temperature will decrease to 50 K
Explanation:
Step 1: Data given
Temperature = 127 °C = 400 K
Pressure = 2.00 atm
The pressure decreases to 0.25 atm
Volume and number of moles do not change
Step 2: Calculate the new pressure
p1/T1=p2/T2
⇒with p1 = The initial pressure = 2.00 atm
⇒with T1 = The initial temperature = 127 °C = 400 K
⇒with p2 = the new pressure = 0.25 atm
⇒with T2 = the new temperature = TO BE DETERMINED
2.00 atm / 400 K = 0.25 atm / T2
0.005 = 0.25 / T2
T2 = 0.25/0.005
T2 = 50 K
The temperature will decrease to 50 K