Explanation:
Let us assume that 5.49 g of Iron chloride is dissolved in 350 ml of 66.0 mM aqueous solution of silver nitrate
Hence, the balanced chemical equation for this reaction is as follows.
So, moles of Iron chloride = 5.49 g of molar mass of Iron chloride
No. of moles =
=
= 0.0338 moles
And, moles of silver nitrate = molarity × volume in L
= 66.0 Mm
or, = 0.066 M × 350 ml
= 0.0231 moles
Therefore, here silver nitrate is the limiting agent
.
Now, we will calculate the moles of which are reacted as follows:.
= 0.01155 moles
Remaining moles of = 0.0338 moles - 0.01155 moles
= 0.02225 mole
Or, 0.0445 moles ions.
Now, we will calculate the molarity as follows.
Molarity =
=
= 0.127 M
Thus, we can conclude that final molarity of chloride anion in the solution is 0.127 M.