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NemiM [27]
3 years ago
14

C6H5-C2H4-COO-CH3-CH2-CH3​

Chemistry
1 answer:
uranmaximum [27]3 years ago
4 0

Answer:

please mention the question

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Please please help !!!
lubasha [3.4K]

Answer:

They don't go below 60

Explanation:

7 0
3 years ago
Which substance will require more energy to heat if all the samples have the same mass? A chart with two columns and nine rows.
Paraphin [41]

Here we have to identify the sample which need more energy to heat the sample 1 degree Celsius.

Among the given elements magnesium will require more energy than the others to heat.

As per the definition of specific heat of a compound, the amount of heat required to increase the temperature of the material 1 degree Celsius is the specific heat of the material.

The given data are-

substance              specific heat

Lead                            0.129

Tin                                0.21

Silver                            0.235

Iron                              0.449

Calcium                        0.647

Granite                         0.803

Aluminium                   0.897

Magnesium                  1.023

From the given data lead, magnesium, iron and aluminium have the specific heat 0.129, 1.023, 0.449 and 0.897 respectively. Thus magnesium will require more energy than the others to heat.

6 0
3 years ago
Helpppp meee plzzzzz
Firdavs [7]

Answer:

11 1/2 cm I think lol

Explanation:

it is in between the 11 and 12 mark

7 0
3 years ago
S shown on the periodic table, the greatest number of elements are which
zavuch27 [327]
The S element is Sulfur and has the atomic mass of 32.06 and has the atomic number of 16. I am not sure of I am correctly answering your question...
7 0
3 years ago
A gas initial volume and pressure is 5m^3 and 101320 Pa and allows to expand up to 12m^3 then what is the final pressure?
Anton [14]

Answer:

New pressure = 42216.66 Pa

Explanation:

Given that,

Initial volume, V₁ = 5 m³

Final pressure, P₁ = 101320 Pa

Final volume, V₂ = 12 m³

We need to find the final pressure of the gas. We know that the relation between pressure and volume is given by :

P\propto \dfrac{1}{V}\\\\P_1V_1=P_2V_2\\\\P_2=\dfrac{P_1V_1}{V_2}\\\\P_2=\dfrac{101320 \times 5}{12}\\\\P_2=42216.67\ Pa

So, the new pressure is equal to 42216.66 Pa.

6 0
3 years ago
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