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kogti [31]
3 years ago
7

lock of mass m2 is attached to a spring of force constant k and m1 . m2. If the system is released from rest, and the spring is

initially not stretched or com- pressed, find an expres- sion for the maximum displacement d of m2
Physics
1 answer:
patriot [66]3 years ago
7 0

Answer:

The maximum displacement of the mass m₂ = \frac{2(m_1-m_2)g}{k}

Explanation:

Kinetic Energy (K) = 1/2mv²

Potential Energy (P) = mgh

Law of Conservation of energy states that total energy of the system remains constant.

i.e; Total energy before collision = Total energy after collision

This implies that: the gravitational potential energy lost by m₁ must be equal to sum of gravitational energy gained by m₂ and the elastic potential energy stored in the spring.

m_1gd = m_2gd+\frac{1}{2}kd^2\\\\m_1g = m_2g+\frac{1}{2}kd\\\\d = \frac{2(m_1-m_2)g}{k}

d = maximum displacement of the mass m₂

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